Xojo Plugin
Xojo Plugin
XML Path Performance Optimizations
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Discusses some important things to know about using Chilkat paths in the Chilkat XML API.Chilkat Xojo Plugin Downloads
Dim success As Boolean
success = False
Dim xml As New Chilkat.Xml
// Let's load XML containing the following:
// <?xml version="1.0" encoding="utf-8"?>
// <xyz>
// <licenses>
// <license>
// <id>1234</id>
// </license>
// <license>
// <id>1234</id>
// </license>
// ...
// My sample XML contains 64,000 "license" nodes ..
// ...
// <license>
// <id>1234</id>
// </license>
// <license>
// <id>1234</id>
// </license>
// </licenses>
// </xyz>
//
success = xml.LoadXmlFile("qa_output/large.xml")
If (success <> True) Then
System.DebugLog(xml.LastErrorText)
Return
End If
// Iterating over the individual "license" nodes with this code snippet is
// extremely slow:
Dim licCount As Int32
licCount = xml.NumChildrenHavingTag("licenses|license")
System.DebugLog("license count = " + Str(licCount))
Dim s As String
Dim i As Int32
i = 0
// If "10" is changed to licCount, then it becomes apparent that this loop gets slower with each iteration.
While i < 10
xml.I = i
s = xml.GetChildContent("licenses|license[i]|id")
System.DebugLog(Str(i) + ": " + s)
i = i + 1
Wend
// The reason it is extremely slow is that the "license[i]" part of the path passed to GetChildContent
// says: find the i'th child of "licenses" having the tag "license". Chilkat cannot assume that all
// children of an XML node have the same tag. Therefore it's not possible to directly access the i'th child.
// Internally, Chilkat must start at the 1st child and iterate until it reaches the i'th child having the
// tag "license".
// For example, imagine if the XML was like this:
// <?xml version="1.0" encoding="utf-8"?>
// <xyz>
// <licenses>
// <license>
// <id>1234</id>
// </license>
// <somethingElse>
// <a>abc</a>
// </somethingElse>
// <license>
// <id>1234</id>
// </license>
// ...
// In the above XML, the 1st "license" is the 1st child of "licenses", but the 2nd "license"
// is the 3rd child of "licenses".
// If you already know that all children have the same tag, there is a shortcut that allows
// for direct access to that child. Just leave off the tag name, like this:
i = 0
// If "10" is changed to licCount, then we can see the time for each loop is the same, and it's fast.
While i < 10
xml.I = i
s = xml.GetChildContent("licenses|[i]|id")
System.DebugLog(Str(i) + ": " + s)
i = i + 1
Wend
// When we pass just the index "[i]", we're saying: Get the i'th child regardless of tag.
// This is extremely fast because internally we can just access the i'th child directly.
// Another performance improvement is to call NumChildrenAt rather than NumChildrenHavingTag.
// For example:
licCount = xml.NumChildrenAt("licenses")
System.DebugLog("licCount = " + Str(licCount))
// NumChildrenAt returns the total number of children at the tag path. If we already know
// all children will have the same tag, we can just get the count