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(VBScript) Iterate Through ZIP Entries Using EntryAt and ZipEntry.GetNextSee more Zip ExamplesThis example demonstrates how to iterate through all entries in a ZIP archive using:
The example prints each ZIP entry's stored filename and whether the entry is a file or directory. This approach is useful when sequentially processing ZIP entries without repeatedly calling Suppose the ZIP archive contains: The example iterates through each entry in the order stored within the ZIP archive.
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) success = 0 set zip = CreateObject("Chilkat.Zip") ' Open an existing ZIP archive. success = zip.OpenZip("c:/temp/example.zip") If (success = 0) Then outFile.WriteLine(zip.LastErrorText) WScript.Quit End If ' A ZIP archive may contain zero entries. If (zip.NumEntries = 0) Then outFile.WriteLine("The ZIP archive is empty.") zip.CloseZip WScript.Quit End If ' ------------------------------------------------------------ ' Get the first ZIP entry. ' ' EntryAt(0,entry) initializes the ZipEntry object so that ' it represents the first entry in the ZIP archive. ' set entry = CreateObject("Chilkat.ZipEntry") success = zip.EntryAt(0,entry) If (success = 0) Then outFile.WriteLine(zip.LastErrorText) WScript.Quit End If ' ------------------------------------------------------------ ' Iterate through all ZIP entries. ' ' GetNext updates the same ZipEntry object so that it ' represents the next entry in the ZIP archive. ' Do While (success = 1) If (entry.IsDirectory = 1) Then outFile.WriteLine("[Directory] " & entry.FileName) Else outFile.WriteLine("[File] " & entry.FileName) End If ' Advance to the next entry. success = entry.GetNext() Loop zip.CloseZip outFile.WriteLine("Done.") outFile.Close |
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