VBScript

Check if a MIME Part is an Image

Demonstrates the Chilkat Mime.IsImage method, which returns whether the Content-Type begins with image/. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: This locates image parts — inline graphics in a multipart/related message, or image attachments — so your code can preview thumbnails, extract them, or handle them differently from documents. It matches any image/ subtype, including image/svg+xml.

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VBScript

Dim fso, outFile
Set fso = CreateObject("Scripting.FileSystemObject")
'Create a Unicode (utf-16) output text file.
Set outFile = fso.CreateTextFile("output.txt", True, True)

success = 0

'  Demonstrates the Mime.IsImage method, which returns whether the Content-Type begins with image/.  It takes no arguments and applies to the current
'  part.  This example iterates the parts of a multipart message and reports which ones match.

set mime = CreateObject("Chilkat.Mime")
success = mime.LoadMimeFile("qa_data/multipart_message.eml")
If (success = 0) Then
    outFile.WriteLine(mime.LastErrorText)
    WScript.Quit
End If

n = mime.NumParts
set part = CreateObject("Chilkat.Mime")

For i = 0 To n - 1
    success = mime.PartAt(i,part)
    If (success = 0) Then
        outFile.WriteLine(mime.LastErrorText)
        WScript.Quit
    End If

    If (part.IsImage()) Then
        outFile.WriteLine("Part " & i & " (" & part.ContentType & ") is an image.")
    End If

Next

outFile.Close