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(VBScript) Example: Mime.GetDecryptCertInfo methodDemonstrates the Note: This example requires Chilkat v11.4.0 or greater.
Dim fso, outFile Set fso = CreateObject("Scripting.FileSystemObject") 'Create a Unicode (utf-16) output text file. Set outFile = fso.CreateTextFile("output.txt", True, True) success = 0 set mime = CreateObject("Chilkat.Mime") ' Load MIME that is has Content-Type like this: ' Content-Type: application/pkcs7-mime; smime-type="enveloped-data"; name="smime.p7m"; smime-type="enveloped-data" success = mime.LoadMimeFile("qa_data/mime/enveloped_data.eml") If (success = 0) Then outFile.WriteLine(mime.LastErrorText) WScript.Quit End If ' Get information about the certificate that would be needed to decrypt. ' An enveloped-data can potentially be decrypted by multiple certificates if it was encrypted in a way that allows it, ' but in most cases, only a single certificate with associated private key (that of the message recipient) is possible. set json = CreateObject("Chilkat.JsonObject") success = mime.GetDecryptCertInfo(json) If (success = 0) Then outFile.WriteLine(mime.LastErrorText) WScript.Quit End If json.EmitCompact = 0 outFile.WriteLine(json.Emit()) ' Sample output: ' { ' "recipientInfo": [ ' { ' "serial": "****", ' "issuerCN": "****" ' } ' ] ' } ' Get each certificate's information like this: i = 0 count = json.SizeOfArray("recipientInfo") Do While i < count json.I = i serial = json.StringOf("recipientInfo[i].serial") issuerCN = json.StringOf("recipientInfo[i].issuerCN") i = i + 1 Loop outFile.Close |
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