VBScript

Example: Mime.GetDecryptCertInfo method

Demonstrates the GetDecryptCertInfo method. VBScript

Dim fso, outFile
Set fso = CreateObject("Scripting.FileSystemObject")
'Create a Unicode (utf-16) output text file.
Set outFile = fso.CreateTextFile("output.txt", True, True)

success = 0

set mime = CreateObject("Chilkat.Mime")

' Load MIME that is has Content-Type like this:
' Content-Type: application/pkcs7-mime; smime-type="enveloped-data"; name="smime.p7m"; smime-type="enveloped-data"
success = mime.LoadMimeFile("qa_data/mime/enveloped_data.eml")
If (success = 0) Then
    outFile.WriteLine(mime.LastErrorText)
    WScript.Quit
End If

' Get information about the certificate that would be needed to decrypt.
' An enveloped-data can potentially be decrypted by multiple certificates if it was encrypted in a way that allows it,
' but in most cases, only a single certificate with associated private key (that of the message recipient) is possible.
set json = CreateObject("Chilkat.JsonObject")
success = mime.GetDecryptCertInfo(json)
If (success = 0) Then
    outFile.WriteLine(mime.LastErrorText)
    WScript.Quit
End If

json.EmitCompact = 0
outFile.WriteLine(json.Emit())

' Sample output:

' {
'   "recipientInfo": [
'     {
'       "serial": "****",
'       "issuerCN": "****"
'     }
'   ]
' }

' Get each certificate's information like this:

i = 0
count = json.SizeOfArray("recipientInfo")
Do While i < count
    json.I = i
    serial = json.StringOf("recipientInfo[i].serial")
    issuerCN = json.StringOf("recipientInfo[i].issuerCN")
    i = i + 1
Loop

outFile.Close