VB.NET
VB.NET
Upload a File to an AI Provider (OpenAI, Google, Antropic, X)
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Uploads a file to an AI provider using the provider's File API and returns theid that can later be used to reference the file in an query. This currently works with ChatGPT, Gemini, Claude, and Grok.
Chilkat VB.NET Downloads
Dim success As Boolean = False
Dim ai As New Chilkat.Ai
' The provider can be "openai", "google", "claude", "grok", or any AI that supports uploading files for later reference by ID.
ai.Provider = "openai"
' Use your provider's API key.
ai.ApiKey = "MY_API_KEY"
' We can upload directly from a file in the filesystem, or from a Chilkat StringBuilder, or from a Chilkat BinData.
' Some AI providers require a content-type.
' Also, some AI providers are picky about what content-type's are accepted.
' Check the AI provider's documentation.
' "application/json" is generally always acceptable.
' "text/plain" can be used as a fallback for any text file.
Dim contentType As String = "application/json"
Dim localFilePath As String = "qa_data/hamlet.json"
Dim filenameOnServer As String = "hamlet.json"
' Upload directly from a file.
Dim file_id As String = ai.UploadFile(localFilePath,contentType)
If (ai.LastMethodSuccess = False) Then
Debug.WriteLine(ai.LastErrorText)
Debug.WriteLine("AI File Upload Failed.")
Else
Debug.WriteLine("File ID: " & file_id)
Debug.WriteLine("File uploaded.")
End If
' Upload from the contents of a StringBuilder
Dim sb As New Chilkat.StringBuilder
success = sb.LoadFile(localFilePath,"utf-8")
If (success = False) Then
Debug.WriteLine(sb.LastErrorText)
Exit Sub
End If
file_id = ai.UploadFileSb(sb,filenameOnServer,contentType)
If (ai.LastMethodSuccess = False) Then
Debug.WriteLine(ai.LastErrorText)
Debug.WriteLine("AI File Upload Failed.")
Else
Debug.WriteLine("File ID: " & file_id)
Debug.WriteLine("File uploaded.")
End If
' Upload from the contents of a BinData
Dim bd As New Chilkat.BinData
success = bd.LoadFile(localFilePath)
If (success = False) Then
Debug.WriteLine(bd.LastErrorText)
Exit Sub
End If
file_id = ai.UploadFileBd(bd,filenameOnServer,contentType)
If (ai.LastMethodSuccess = False) Then
Debug.WriteLine(ai.LastErrorText)
Debug.WriteLine("AI File Upload Failed.")
Else
Debug.WriteLine("File ID: " & file_id)
Debug.WriteLine("File uploaded.")
End If