![]() |
Chilkat HOME Android™ AutoIt C C# C++ Chilkat2-Python CkPython Classic ASP DataFlex Delphi DLL Go Java JavaScript Node.js Objective-C PHP Extension Perl PowerBuilder PowerShell PureBasic Ruby SQL Server Swift Tcl Unicode C Unicode C++ VB.NET VBScript Visual Basic 6.0 Visual FoxPro Xojo Plugin
(Visual Basic 6.0) Get ZIP Directory Information as XMLSee more Zip Examples This example demonstrates how to use the The returned XML describes the files currently contained in the ZIP object Note: This example requires Chilkat v11.0.0 or greater.
Dim success As Long success = 0 success = 0 ' Open an existing ZIP archive. Dim zip As New ChilkatZip success = zip.OpenZip("example.zip") If (success = 0) Then Debug.Print zip.LastErrorText Exit Sub End If ' Get the ZIP directory information as XML. Dim xml As String xml = zip.GetDirectoryAsXML() Debug.Print xml ' Suppose the ZIP contains: ' data/config/settings.json ' docs/readme.txt ' images/logo.png ' The XML contains one element for each ZIP entry. ' Example: ' ' <?xml version="1.0" encoding="utf-8"?> ' <zip_contents> ' <dir name="data"> ' <dir name="config"> ' <file>settings.json</file> ' </dir> ' </dir> ' <dir name="docs"> ' <file>readme.txt</file> ' </dir> ' <dir name="images"> ' <file>logo.png</file> ' </dir> ' </zip_contents> zip.CloseZip Debug.Print "Done." |
||||
© 2000-2026 Chilkat Software, Inc. All Rights Reserved.