Unicode C++

Check if a MIME Part is XML

Demonstrates the Chilkat Mime.IsXml method, which returns true only for text/xml or application/xml. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Identifying an XML part matters in machine-to-machine messaging — SOAP, EDI, structured data payloads — where you want to hand the body to an XML parser. Note it matches only the two canonical XML media types and not structured-suffix types like application/xhtml+xml, so check the exact type when those are relevant.

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Unicode C++

#include <CkMimeW.h>

void ChilkatSample(void)
    {
    bool success = false;

    //  Demonstrates the Mime.IsXml method, which returns whether the Content-Type is text/xml or application/xml.  It takes no arguments and applies to the current
    //  part.  This example iterates the parts of a multipart message and reports which ones match.

    CkMimeW mime;
    success = mime.LoadMimeFile(L"qa_data/multipart_message.eml");
    if (success == false) {
        wprintf(L"%s\n",mime.lastErrorText());
        return;
    }

    int n = mime.get_NumParts();
    CkMimeW part;
    int i;
    for (i = 0; i <= n - 1; i++) {
        success = mime.PartAt(i,part);
        if (success == false) {
            wprintf(L"%s\n",mime.lastErrorText());
            return;
        }

        if (part.IsXml()) {
            wprintf(L"Part %d (%s) is XML.\n",i,part.contentType());
        }

    }
    }