Swift

Unzip Files Matching a Pattern (such as *.xml)

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Example code to unzip Files Matching a Pattern (such as *.xml) Swift

func chilkatTest() {
    var success: Bool = false

    // This example works with the .zip located at http://www.example-code.com/data/test.zip

    // This example assumes the Chilkat API to have been previously unlocked.
    // See Global Unlock Sample for sample code.

    // First, let's download the .zip
    let http = CkoHttp()!
    success = http.download(url: "http://www.example-code.com/data/test.zip", saveToPath: "qa_test/test.zip")
    if success != true {
        print("\(http.lastErrorText!)")
        return
    }

    let zip = CkoZip()!

    success = zip.open(zipPath: "qa_test/test.zip")
    if success != true {
        print("\(zip.lastErrorText!)")
        return
    }

    // Show what's in the .zip by getting the directory as XML.
    var zipContentsXml: String? = zip.getDirectoryAsXML()
    if zip.lastMethodSuccess != true {
        print("\(zip.lastErrorText!)")
        return
    }

    print("\(zipContentsXml!)")

    // In this case, the contents of our .zip look like this:
    // <?xml version="1.0" encoding="utf-8" ?>
    // <zip_contents>
    //     <dir name="test">
    //         <dir name="abc">
    //             <dir name="123">
    //                 <file>ecc_public.pem</file>
    //                 <file>starfish.jpg</file>
    //             </dir>
    //             <file>comodo-certificates.pem</file>
    //             <file>pigs.xml</file>
    //         </dir>
    //         <file>COMODORSACertificationAuthority.crt</file>
    //         <file>hamlet.xml</file>
    //     </dir>
    // </zip_contents>

    // ------------------------------------------------------------------------
    // If we wish to unzip only .xml files, use "*.xml" for the pattern\
    // Unzip to the "qa_output" directory relative to our current working directory.
    // (You may unzip to an absolute path by passing an absolute path, such as "/someDir" or
    // "C:/someDir", etc.)
    // This will unzip only the .xml files.  The relative directory structure within
    // the .zip will be created in the local filesystem under the unzip directory
    // path passed in the first argument, which in this case is "qa_output".
    var count: Int = zip.unzip(matching: "qa_output", pattern: "*.xml", verbose: true).intValue
    if count < 0 {
        print("\(zip.lastErrorText!)")
        return
    }

    print("unzipped \(count) matching file(s).")

    // ------------------------------------------------------------------------
    // If we wish to unzip only files under the "123" directory, we can do this:
    count = zip.unzip(matching: "qa_output2", pattern: "*/123/*", verbose: true).intValue
    if count < 0 {
        print("\(zip.lastErrorText!)")
        return
    }

    print("unzipped \(count) matching file(s).")

    // ------------------------------------------------------------------------
    // If no asterisk character is used, then the match must be exact.
    // For example, to unzip "test/hamlet.xml" we must pass the exact path
    // as it is in the .zip.  We cannot just pass "hamlet.xml".
    count = zip.unzip(matching: "qa_output3", pattern: "test/hamlet.xml", verbose: true).intValue
    if count < 0 {
        print("\(zip.lastErrorText!)")
        return
    }

    print("unzipped \(count) matching file(s).")

    // ------------------------------------------------------------------------
    // If we want to unzip any file named "hamlet.xml" found in any sub-directory...
    count = zip.unzip(matching: "qa_output4", pattern: "*/hamlet.xml", verbose: true).intValue
    if count < 0 {
        print("\(zip.lastErrorText!)")
        return
    }

    print("unzipped \(count) matching file(s).")

}