Swift
Swift
SSH Through a SOCKS Proxy
See more SSH Examples
Demonstrates connecting to an SSH server through a SOCKS4 or SOCKS5 proxy. Set the SOCKS properties before calling Connect, and set SocksVersion to match the proxy server.
Background: SOCKS is a general-purpose TCP relay, so unlike an HTTP proxy it is designed from the start to carry arbitrary protocols — usually the smoother option for SSH. The version matters: SOCKS4 supports only a username with no password, while SOCKS5 supports full login/password authentication as well as IPv6 and remote DNS resolution. Note this is the inverse of dynamic port forwarding: here a SOCKS proxy is used to reach the SSH server, rather than SSH providing a SOCKS proxy.
Chilkat Swift Downloads
func chilkatTest() {
var success: Bool = false
// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
// Demonstrates connecting to an SSH server through a SOCKS4 or SOCKS5 proxy.
let ssh = CkoSsh()!
// Set the SOCKS proxy properties before connecting. The hostname may be a domain name or an
// IP address.
ssh.socksHostname = "socks.example.com"
ssh.socksPort = 1080
ssh.socksUsername = "mySocksLogin"
ssh.socksPassword = "mySocksPassword"
// Set the version to match the proxy server: 4 or 5.
// Note: SOCKS4 supports only a username, with no password. SOCKS5 supports full
// login/password authentication.
ssh.socksVersion = 5
var hostname: String? = "ssh.example.com"
var port: Int = 22
success = ssh.connect(hostname: hostname, port: port)
if success == false {
print("\(ssh.lastErrorText!)")
return
}
print("Connected to the SSH server through the SOCKS proxy.")
// Normally you would not hard-code the password in source. You should instead obtain it
// from an interactive prompt, environment variable, or a secrets vault.
var password: String? = "mySshPassword"
success = ssh.authenticatePw(login: "mySshLogin", password: password)
if success == false {
print("\(ssh.lastErrorText!)")
return
}
// ... use the SSH connection normally ...
ssh.disconnect()
}