Swift

Continue SSH Keyboard-Interactive Authentication

Demonstrates the Chilkat Ssh.ContinueKeyboardAuth method, which submits a response to a keyboard-interactive prompt. The only argument is the response text; for a request containing multiple prompts, an XML response is supplied instead. It returns XML indicating the next prompt or the final result.

Background: This is the second half of the keyboard-interactive exchange started by StartKeyboardAuth. A server may issue several rounds of prompts, so a robust client loops: submit answers, read the returned XML, and continue until authentication succeeds or fails. Prompt responses are typically secrets, so obtain them from interactive input rather than embedding them in code.

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Swift


func chilkatTest() {
    var success: Bool = false

    //  Demonstrates the Ssh.ContinueKeyboardAuth method, which submits a response to a
    //  keyboard-interactive prompt.  The only argument is the response.  For multiple prompts, an
    //  XML response is supplied instead.

    let ssh = CkoSsh()!

    //  Connect to the SSH server.  Port 22 is the usual SSH port.
    var sshPort: Int = 22
    success = ssh.connect(hostname: "ssh.example.com", port: sshPort)
    if success == false {
        print("\(ssh.lastErrorText!)")
        return
    }

    //  Begin keyboard-interactive authentication to receive the server's prompt(s).
    var infoRequestXml: String? = ssh.startKeyboardAuth(login: "mySshLogin")
    if ssh.lastMethodSuccess == false {
        print("\(ssh.lastErrorText!)")
        return
    }

    //  Normally you would not hard-code the response (typically the password) in source.  You
    //  should instead obtain it from an interactive prompt.
    var response: String? = "mySshPassword"

    //  Submit the response.  The returned XML indicates the next prompt or the final result.
    var result: String? = ssh.continueKeyboardAuth(response: response)
    if ssh.lastMethodSuccess == false {
        print("\(ssh.lastErrorText!)")
        return
    }

    print("\(result!)")

    ssh.disconnect()

}