Swift
Swift
Poll an SSH Channel for Incoming Data
See more SSH Examples
Demonstrates the Chilkat Ssh.ChannelPoll method, which polls a channel for incoming messages, waiting at most the given number of milliseconds. The first argument is the channel number and the second is the poll timeout; pass 0 for a nonblocking poll.
The integer return value is -1 on error, -2 if nothing arrived before the timeout, 0 if EOF or channel close was processed, or — when greater than 0 — the total bytes currently buffered for the channel (not the bytes newly received by this call).
Background:
ChannelPoll gives you an explicit, per-call wait, which is what an event loop or responsive UI needs — poll briefly, do other work, poll again. Importantly, the timeout you pass governs the wait: shorter ReadTimeoutMs or IdleTimeoutMs values do not cut it short. A -2 return simply means nothing new arrived, which is normal when polling.Chilkat Swift Downloads
func chilkatTest() {
var success: Bool = false
// Demonstrates the Ssh.ChannelPoll method, which polls a channel for incoming messages, waiting
// at most the given number of milliseconds. The 1st argument is the channel number and the 2nd
// is the poll timeout. Pass 0 for a nonblocking poll.
let ssh = CkoSsh()!
var sshPort: Int = 22
success = ssh.connect(hostname: "ssh.example.com", port: sshPort)
if success == false {
print("\(ssh.lastErrorText!)")
return
}
// Normally you would not hard-code the password in source. You should instead obtain it
// from an interactive prompt, environment variable, or a secrets vault.
var password: String? = "mySshPassword"
success = ssh.authenticatePw(login: "mySshLogin", password: password)
if success == false {
print("\(ssh.lastErrorText!)")
return
}
var channelNum: Int = ssh.openSessionChannel().intValue
if channelNum < 0 {
print("\(ssh.lastErrorText!)")
return
}
// Start a shell WITHOUT requesting a PTY. Without a PTY the shell sees it is connected to a
// raw data pipe and enters non-interactive mode: it suppresses the command prompt, does not
// echo typed commands back, and skips interactive login scripts. The output is therefore
// clean and easily parseable -- but because no prompt is ever sent, code must not wait for
// one. Instead, have each command print a predictable marker, or wait for EOF / channel close.
success = ssh.sendReqShell(channelNum: channelNum)
if success == false {
print("\(ssh.lastErrorText!)")
return
}
success = ssh.channelSendString(channelNum: channelNum, strData: "date\n", charset: "utf-8")
if success == false {
print("\(ssh.lastErrorText!)")
return
}
// Wait up to 3 seconds for channel data.
var pollTimeoutMs: Int = 3000
// The return value is: -1 on error, -2 if nothing arrived before the timeout, 0 if EOF or
// channel close was processed, or the total number of buffered bytes when greater than 0.
var result: Int = ssh.channelPoll(channelNum: channelNum, pollTimeoutMs: pollTimeoutMs).intValue
if result == -1 {
print("\(ssh.lastErrorText!)")
return
}
if result == -2 {
print("No channel data arrived before the timeout.")
}
if result == 0 {
print("EOF or channel close was processed. Buffered data may still remain.")
}
if result > 0 {
print("Total bytes buffered: \(result)")
}
var output: String? = ssh.getReceivedText(channelNum: channelNum, charset: "utf-8")
if ssh.lastMethodSuccess == false {
print("\(ssh.lastErrorText!)")
return
}
print("\(output!)")
ssh.disconnect()
}