SQL Server

Get ZIP Directory Information as XML

See more Zip Examples

This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

SQL Server

-- Important: See this note about string length limitations for strings returned by sp_OAMethod calls.
--
CREATE PROCEDURE ChilkatSample
AS
BEGIN
    DECLARE @hr int
    -- Important: Do not use nvarchar(max).  See the warning about using nvarchar(max).
    DECLARE @sTmp0 nvarchar(4000)
    DECLARE @success int
    SELECT @success = 0

    SELECT @success = 0

    -- Open an existing ZIP archive.
    DECLARE @zip int
    EXEC @hr = sp_OACreate 'Chilkat.Zip', @zip OUT
    IF @hr <> 0
    BEGIN
        PRINT 'Failed to create ActiveX component'
        RETURN
    END

    EXEC sp_OAMethod @zip, 'OpenZip', @success OUT, 'example.zip'
    IF @success = 0
      BEGIN
        EXEC sp_OAGetProperty @zip, 'LastErrorText', @sTmp0 OUT
        PRINT @sTmp0
        EXEC @hr = sp_OADestroy @zip
        RETURN
      END

    -- Get the ZIP directory information as XML.
    DECLARE @xml nvarchar(4000)
    EXEC sp_OAMethod @zip, 'GetDirectoryAsXML', @xml OUT


    PRINT @xml

    -- Suppose the ZIP contains:

    -- data/config/settings.json
    -- docs/readme.txt
    -- images/logo.png

    -- The XML contains one element for each ZIP entry.
    -- Example:
    -- 
    -- <?xml version="1.0" encoding="utf-8"?>
    -- <zip_contents>
    --     <dir name="data">
    --         <dir name="config">
    --             <file>settings.json</file>
    --         </dir>
    --     </dir>
    --     <dir name="docs">
    --         <file>readme.txt</file>
    --     </dir>
    --     <dir name="images">
    --         <file>logo.png</file>
    --     </dir>
    -- </zip_contents>

    EXEC sp_OAMethod @zip, 'CloseZip', NULL


    PRINT 'Done.'

    EXEC @hr = sp_OADestroy @zip


END
GO