Rust

Iterate over Direct Child Nodes by Index

See more XML Examples

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Rust

let xml = chilkat::Xml::new();

// The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
if xml.load_xml_file("get_child.xml").is_err() {
    println!("{}", xml.last_error_text());
    return;
}

// The NumChildren property contains the number of direct
// child nodes.  Note: The child nodes under "xyz" are NOT
// direct children of "root".  Therefore, the "root" node has
// 7 direct children
println!("NumChildren = {}", xml.num_children());

// Iterate over the direct children by index. The first child
// is at index 0.
for i in 0..xml.num_children() {
    //  access the tag and content directly by index:
    println!("{}: {} : {}", i, xml.get_child_tag_by_index(i).unwrap_or_default(), xml.get_child_content_by_index(i).unwrap_or_default());

}

println!("-----");

// Do the same as the above loop, but get the child node
// and access the Tag and Content properties:
for i in 0..xml.num_children() {
    let child = xml.get_child(i).unwrap();
    println!("{}: {} : {}", i, child.tag(), child.content());

}

println!("-----");

// Do the same as the above loop, but instead of creating
// a new object instance for each child, call GetChild2 to
// update the object's reference instead.
for i in 0..xml.num_children() {
    // Navigate to the Nth child.  
    let _ = xml.get_child2(i).is_ok();
    println!("{}: {} : {}", i, xml.tag(), xml.content());
    // Navigate back up to the parent:
    let _ = xml.get_parent2().is_ok();
}

println!("-----");

// Notice that the Content of the "xyz" node is empty.  This is correct.
// The "xyz" node has no Content, but 2 direct children.