Ruby

Traverse Direct Children via FirstChild / NextSibling, or LastChild / PreviousSibling

See more XML Examples

Demonstrates some ways to iterate over direct child nodes using the FirstChild / NextSibling and LastChild / PreviousSibling methods.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Ruby

require 'chilkat'

success = false

xml = Chilkat::CkXml.new()

success = xml.LoadXmlFile("qa_data/xml/fruit.xml")
if (success != true)
    print xml.lastErrorText() + "\n";
    exit
end

# Iterate over the direct children by using FirstChild / NextSibling
# child is a CkXml
child = xml.FirstChild()
bContinue = xml.get_LastMethodSuccess()
while (bContinue == true)
    print child.tag() + " : " + child.content() + "\n";
    # nextSibling is a CkXml
    nextSibling = child.NextSibling()
    bContinue = child.get_LastMethodSuccess()

    # child is a CkXml
    child = nextSibling
end
print "-----" + "\n";

# Do the same, but with FirstChild2 / NextSibling2 to avoid
# creating so many XML object instances:
success = xml.FirstChild2()
while success == true
    print xml.tag() + " : " + xml.content() + "\n";
    success = xml.NextSibling2()
end
# Revert back up to the parent:
success = xml.GetParent2()

print "-----" + "\n";

# Iterate in reverse order using LastChild / PreviousSibling
# child is a CkXml
child = xml.LastChild()
bContinue = xml.get_LastMethodSuccess()
while (bContinue == true)
    print child.tag() + " : " + child.content() + "\n";
    # prevSibling is a CkXml
    prevSibling = child.PreviousSibling()
    bContinue = child.get_LastMethodSuccess()

    # child is a CkXml
    child = prevSibling
end
print "-----" + "\n";

# Do the same, but with LastChild2 / PreviousSibling2 to avoid
# creating so many XML object instances:
success = xml.LastChild2()
while success == true
    print xml.tag() + " : " + xml.content() + "\n";
    success = xml.PreviousSibling2()
end
# Revert back up to the parent:
success = xml.GetParent2()