CkPython
CkPython
Poll an SSH Channel for Incoming Data
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Demonstrates the Chilkat Ssh.ChannelPoll method, which polls a channel for incoming messages, waiting at most the given number of milliseconds. The first argument is the channel number and the second is the poll timeout; pass 0 for a nonblocking poll.
The integer return value is -1 on error, -2 if nothing arrived before the timeout, 0 if EOF or channel close was processed, or — when greater than 0 — the total bytes currently buffered for the channel (not the bytes newly received by this call).
Background:
ChannelPoll gives you an explicit, per-call wait, which is what an event loop or responsive UI needs — poll briefly, do other work, poll again. Importantly, the timeout you pass governs the wait: shorter ReadTimeoutMs or IdleTimeoutMs values do not cut it short. A -2 return simply means nothing new arrived, which is normal when polling.Chilkat CkPython Downloads
import sys
import chilkat
success = False
# Demonstrates the Ssh.ChannelPoll method, which polls a channel for incoming messages, waiting
# at most the given number of milliseconds. The 1st argument is the channel number and the 2nd
# is the poll timeout. Pass 0 for a nonblocking poll.
ssh = chilkat.CkSsh()
sshPort = 22
success = ssh.Connect("ssh.example.com",sshPort)
if (success == False):
print(ssh.lastErrorText())
sys.exit()
# Normally you would not hard-code the password in source. You should instead obtain it
# from an interactive prompt, environment variable, or a secrets vault.
password = "mySshPassword"
success = ssh.AuthenticatePw("mySshLogin",password)
if (success == False):
print(ssh.lastErrorText())
sys.exit()
channelNum = ssh.OpenSessionChannel()
if (channelNum < 0):
print(ssh.lastErrorText())
sys.exit()
# Start a shell WITHOUT requesting a PTY. Without a PTY the shell sees it is connected to a
# raw data pipe and enters non-interactive mode: it suppresses the command prompt, does not
# echo typed commands back, and skips interactive login scripts. The output is therefore
# clean and easily parseable -- but because no prompt is ever sent, code must not wait for
# one. Instead, have each command print a predictable marker, or wait for EOF / channel close.
success = ssh.SendReqShell(channelNum)
if (success == False):
print(ssh.lastErrorText())
sys.exit()
success = ssh.ChannelSendString(channelNum,"date\n","utf-8")
if (success == False):
print(ssh.lastErrorText())
sys.exit()
# Wait up to 3 seconds for channel data.
pollTimeoutMs = 3000
# The return value is: -1 on error, -2 if nothing arrived before the timeout, 0 if EOF or
# channel close was processed, or the total number of buffered bytes when greater than 0.
result = ssh.ChannelPoll(channelNum,pollTimeoutMs)
if (result == -1):
print(ssh.lastErrorText())
sys.exit()
if (result == -2):
print("No channel data arrived before the timeout.")
if (result == 0):
print("EOF or channel close was processed. Buffered data may still remain.")
if (result > 0):
print("Total bytes buffered: " + str(result))
output = ssh.getReceivedText(channelNum,"utf-8")
if (ssh.get_LastMethodSuccess() == False):
print(ssh.lastErrorText())
sys.exit()
print(output)
ssh.Disconnect()