CkPython
CkPython
Get a Remote File's Owner
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Demonstrates the Chilkat SFtp.GetFileOwner method, which returns a remote file's owner. The arguments are the remote path (or handle), whether symbolic links are followed, and whether the first argument is a handle.
Background: Ownership determines who may read, write, or change a file under Unix permission rules, so reading the owner is useful for auditing or for deciding whether an operation will be allowed. Note that a server may report the owner as a numeric UID rather than a name if it cannot resolve the account, and that ownership is a Unix concept — servers on other platforms may return an empty or synthetic value.
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import sys
import chilkat
success = False
# Demonstrates the SFtp.GetFileOwner method, which returns a remote file's owner. The 1st
# argument is the remote path (or handle), the 2nd selects whether symbolic links are followed,
# and the 3rd indicates whether the 1st argument is a handle.
sftp = chilkat.CkSFtp()
# Connect, authenticate, and initialize the SFTP subsystem.
port = 22
success = sftp.Connect("sftp.example.com",port)
if (success == False):
print(sftp.lastErrorText())
sys.exit()
# Normally you would not hard-code the password in source. You should instead obtain it
# from an interactive prompt, environment variable, or a secrets vault.
password = "mySshPassword"
success = sftp.AuthenticatePw("mySshLogin",password)
if (success == False):
print(sftp.lastErrorText())
sys.exit()
success = sftp.InitializeSftp()
if (success == False):
print(sftp.lastErrorText())
sys.exit()
# The 2nd argument (bFollowLinks) selects whether a symbolic link is followed to its target.
# The 3rd argument (bIsHandle) is False here because the 1st argument is a path, not an
# open handle.
bFollowLinks = True
bIsHandle = False
owner = sftp.getFileOwner("subdir/report.pdf",bFollowLinks,bIsHandle)
if (sftp.get_LastMethodSuccess() == False):
print(sftp.lastErrorText())
sys.exit()
print("Owner: " + owner)
sftp.Disconnect()