CkPython

REST through HTTP Proxy

See more REST Examples

Demonstrates how to connect through an HTTP proxy to make REST API calls. CkPython

import sys
import chilkat

success = False

# This example requires the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

# This example connects to a REST server through an HTTP proxy.
# It will connect to the Amazon AWS service for this example.
rest = chilkat.CkRest()
socket = chilkat.CkSocket()

# Set the HTTP proxy domain or IP address, and port.
socket.put_HttpProxyHostname("192.168.1.100")
socket.put_HttpProxyPort(8088)

# We want to tell the socket object that we're doing HTTP over the proxy connection.
# This is because an HTTP proxy used for other protocols (IMAP, SMTP, SSH, FTP, etc.) 
# can require some internal differences in behavior (i.e. how we do things).
socket.put_HttpProxyForHttp(True)

# Other properties exist for specifying a proxy login, password, and authentication method (such as NTLM),
# but these are not used in this example.

# Connect through the HTTP proxy to the Amazon AWS server for the S3 service.
bTls = True
port = 443
maxWaitMs = 5000
success = socket.Connect("s3.amazonaws.com",port,bTls,maxWaitMs)
if (success != True):
    print("Connect Failure Error Code: " + str(socket.get_ConnectFailReason()))
    print(socket.lastErrorText())
    sys.exit()

# Use the proxied TLS connection:
success = rest.UseConnection(socket,True)
if (success != True):
    print(rest.lastErrorText())
    sys.exit()

# Provide AWS credentials for the REST call.
authAws = chilkat.CkAuthAws()
authAws.put_AccessKey("AWS_ACCESS_KEY")
authAws.put_SecretKey("AWS_SECRET_KEY")
authAws.put_ServiceName("s3")
success = rest.SetAuthAws(authAws)

# List all buckets for the account...
responseXml = rest.fullRequestNoBody("GET","/")
if (rest.get_LastMethodSuccess() != True):
    print(rest.lastErrorText())
    sys.exit()

xml = chilkat.CkXml()
success = xml.LoadXml(responseXml)

# Show the full XML returned.
print(xml.getXml())

# Iterate over the buckets, showing each bucket name.
success = xml.FindChild2("Buckets")
if (xml.FirstChild2() == True):
    print(xml.getChildContent("Name"))
    while (xml.NextSibling2() == True) :
        print(xml.getChildContent("Name"))

# Move the internal pointer back to the root node.
xml.GetRoot2()