CkPython

Check if a MIME Part is XML

Demonstrates the Chilkat Mime.IsXml method, which returns true only for text/xml or application/xml. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Identifying an XML part matters in machine-to-machine messaging — SOAP, EDI, structured data payloads — where you want to hand the body to an XML parser. Note it matches only the two canonical XML media types and not structured-suffix types like application/xhtml+xml, so check the exact type when those are relevant.

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import sys
import chilkat

success = False

#  Demonstrates the Mime.IsXml method, which returns whether the Content-Type is text/xml or application/xml.  It takes no arguments and applies to the current
#  part.  This example iterates the parts of a multipart message and reports which ones match.

mime = chilkat.CkMime()
success = mime.LoadMimeFile("qa_data/multipart_message.eml")
if (success == False):
    print(mime.lastErrorText())
    sys.exit()

n = mime.get_NumParts()
part = chilkat.CkMime()

for i in range(0,n):
    success = mime.PartAt(i,part)
    if (success == False):
        print(mime.lastErrorText())
        sys.exit()

    if (part.IsXml()):
        print("Part " + str(i) + " (" + part.contentType() + ") is XML.")