CkPython

Check if a MIME Part is Plain Text

Demonstrates the Chilkat Mime.IsPlainText method, which returns whether the Content-Type is exactly text/plain. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Inside a multipart/alternative, this is how you pick out the plain-text rendering — the fallback to show when HTML cannot be displayed, or the version to index for search. It is the specific counterpart to IsHtml.

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import sys
import chilkat

success = False

#  Demonstrates the Mime.IsPlainText method, which returns whether the Content-Type is text/plain.  It takes no arguments and applies to the current
#  part.  This example iterates the parts of a multipart message and reports which ones match.

mime = chilkat.CkMime()
success = mime.LoadMimeFile("qa_data/multipart_message.eml")
if (success == False):
    print(mime.lastErrorText())
    sys.exit()

n = mime.get_NumParts()
part = chilkat.CkMime()

for i in range(0,n):
    success = mime.PartAt(i,part)
    if (success == False):
        print(mime.lastErrorText())
        sys.exit()

    if (part.IsPlainText()):
        print("Part " + str(i) + " (" + part.contentType() + ") is plain text.")