CkPython

HTTP POST (Duplicate Simple HTML Form POST)

Demonstrates how to duplicate a simple HTML form POST. CkPython

import sys
import chilkat

success = False

# This example requires the Chilkat API to have been previously unlocked.
# See Global Unlock Sample for sample code.

req = chilkat.CkHttpRequest()
http = chilkat.CkHttp()

# This example simulates this FORM:
# <form action="echoPost.asp" method="post">
# First name: <input type="text" name="firstName"><br />
# Last name: <input type="text" name="lastName"><br />
# <input type="submit" value="Submit">
# </form>
# The online FORM is found at this URL:
# https://www.chilkatsoft.com/simpleForm.html

# Build an HTTP POST Request:
req.put_HttpVerb("POST")

# The FORM target is http://www.chilkatsoft.com/processPost.asp
# An easy way of filling out most of the HTTP request object
# is to call SetFromUrl:
req.SetFromUrl("https://www.chilkatsoft.com/echoPost.asp")

# Send form params using application/x-www-form-urlencoded
req.put_ContentType("application/x-www-form-urlencoded")

# The only remaining task is to add the params to the 
# HTTP request object:
req.AddParam("firstName","Matt")
req.AddParam("lastName","Jones")

# Send the HTTP POST and get the response.
# The POST is being sent to chilkatsoft.com, on port 443 (using TLS)
domain = "chilkatsoft.com"
port = 443
tls = True

# The HTTP POST is sent here:
resp = chilkat.CkHttpResponse()
success = http.HttpSReq(domain,port,tls,req,resp)
if (success == False):
    print(http.lastErrorText())
    sys.exit()

# Display the HTML source of the page returned.
print(resp.bodyStr())