PowerShell Requires Chilkat v11.0.0+

Get ZIP Directory Information as XML

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This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

PowerShell

Add-Type -Path "C:\chilkat\ChilkatDotNet47-x64\ChilkatDotNet47.dll"

$success = $false

#  Open an existing ZIP archive.
$zip = New-Object Chilkat.Zip

$success = $zip.OpenZip("example.zip")
if ($success -eq $false) {
    $($zip.LastErrorText)
    exit
}

#  Get the ZIP directory information as XML.
$xml = $zip.GetDirectoryAsXML()

$($xml)

#  Suppose the ZIP contains:

#  data/config/settings.json
#  docs/readme.txt
#  images/logo.png

#  The XML contains one element for each ZIP entry.
#  Example:
#  
#  <?xml version="1.0" encoding="utf-8"?>
#  <zip_contents>
#      <dir name="data">
#          <dir name="config">
#              <file>settings.json</file>
#          </dir>
#      </dir>
#      <dir name="docs">
#          <file>readme.txt</file>
#      </dir>
#      <dir name="images">
#          <file>logo.png</file>
#      </dir>
#  </zip_contents>

$zip.CloseZip()

$("Done.")