PowerShell

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. PowerShell

Add-Type -Path "C:\chilkat\ChilkatDotNet47-x64\ChilkatDotNet47.dll"

$success = $false

# This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

# <?xml version="1.0" encoding="UTF-8" ?>
# <someEntries>
#     <entry>
#         <id>123</id>
#         <updated>2017-07-19T05:19:57.761Z</updated>
#         <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
#         <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
#         <title>George Costanza</title>
#          <gd:name>
#             <gd:fullName>George Costanza</gd:fullName>
#             <gd:givenName>George</gd:givenName>
#             <gd:familyName>Costanza</gd:familyName>
#         </gd:name>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
#         <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
#         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
#         <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
#     </entry>
# </someEntries>
# 

$xml = New-Object Chilkat.Xml

$success = $xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml")

$numPhoneNumbers = $xml.NumChildrenHavingTag("entry|*:phoneNumber")
$i = 0
while ($i -lt $numPhoneNumbers) {
    $xPhoneNumber = $xml.GetNthChildWithTag("entry|*:phoneNumber",$i)
    $($xPhoneNumber.Content)

    $i = $i + 1
}

$("----")

$numGroupMemberships = $xml.NumChildrenHavingTag("entry|*:groupMembershipInfo")
$i = 0
while ($i -lt $numGroupMemberships) {
    $xMembership = $xml.GetNthChildWithTag("entry|*:groupMembershipInfo",$i)
    $($xMembership.GetAttrValue("href"))

    $i = $i + 1
}