PHP ActiveX

HTTP POST (Duplicate Simple HTML Form POST)

Demonstrates how to duplicate a simple HTML form POST. PHP ActiveX

<?php

$success = 0;

// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.

$req = new COM("Chilkat.HttpRequest");
$http = new COM("Chilkat.Http");

// This example simulates this FORM:
// <form action="echoPost.asp" method="post">
// First name: <input type="text" name="firstName"><br />
// Last name: <input type="text" name="lastName"><br />
// <input type="submit" value="Submit">
// </form>
// The online FORM is found at this URL:
// https://www.chilkatsoft.com/simpleForm.html

// Build an HTTP POST Request:
$req->HttpVerb = 'POST';

// The FORM target is http://www.chilkatsoft.com/processPost.asp
// An easy way of filling out most of the HTTP request object
// is to call SetFromUrl:
$req->SetFromUrl('https://www.chilkatsoft.com/echoPost.asp');

// Send form params using application/x-www-form-urlencoded
$req->ContentType = 'application/x-www-form-urlencoded';

// The only remaining task is to add the params to the 
// HTTP request object:
$req->AddParam('firstName','Matt');
$req->AddParam('lastName','Jones');

// Send the HTTP POST and get the response.
// The POST is being sent to chilkatsoft.com, on port 443 (using TLS)
$domain = 'chilkatsoft.com';
$port = 443;
$tls = 1;

// The HTTP POST is sent here:
$resp = new COM("Chilkat.HttpResponse");
$success = $http->HttpSReq($domain,$port,$tls,$req,$resp);
if ($success == 0) {
    print $http->LastErrorText . "\n";
    exit;
}

// Display the HTML source of the page returned.
print $resp->BodyStr . "\n";

?>