Pascal (Lazarus/Delphi)
Pascal (Lazarus/Delphi)
Tips on Matching Encryption with another System
See more Encryption Examples
This example provides tips on matching encryption results produced by another system.Chilkat Pascal (Lazarus/Delphi) Downloads
program ChilkatDemo;
// Demonstrates using the Chilkat Pascal wrapper via the C bridge DLL.
// Builds as a console application under Lazarus (FPC) or Delphi.
{$IFDEF FPC}
{$MODE DELPHI}
{$ENDIF}
{$APPTYPE CONSOLE}
uses
{$IFDEF UNIX}
cthreads,
{$ENDIF}
SysUtils,
CkDllLoader,
Chilkat.Crypt2;
// ---------------------------------------------------------------------------
procedure RunDemo;
var
crypt: TCrypt2;
ivHex1: string;
ivHex2: string;
keyHex: string;
begin
// This example assumes the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.
crypt := TCrypt2.Create;
// Let's examine 256-bit AES encryption in CBC mode.
// CBC mode is Cipher Block Chaining, and it uses an IV (initialization vector)
crypt.CryptAlgorithm := 'aes';
crypt.CipherMode := 'cbc';
crypt.KeyLength := 256;
crypt.PaddingScheme := 0;
ivHex1 := '000102030405060708090A0B0C0D0E0F';
ivHex2 := 'FF0102030405060708090A0B0C0D0E0F';
crypt.SetEncodedIV(ivHex1,'hex');
keyHex := '000102030405060708090A0B0C0D0E0F101112131415161718191A1B1C1D1E1F';
crypt.SetEncodedKey(keyHex,'hex');
// Matching encryption requires all of the above settings to be matched exactly.
// Let's get our output in hex format so we can easily see the values of the encrypted bytes.
crypt.EncodingMode := 'hex';
// Encrypt something small:
WriteLn(crypt.EncryptStringENC('Hello'));
// The result is 5B827AB3B4F9F2292C2B74C8A6C99A3D
// This 16 bytes -- exactly one AES encryption block.
// Let's change only the padding scheme.
crypt.PaddingScheme := 3;
// Encrypt again:
WriteLn(crypt.EncryptStringENC('Hello'));
// The result is entirely different: 469C28CC576069F807891FEE2DE76D68
// The padding scheme only affects the very last block of output. Therefore,
// if all settings match except for the padding scheme, we're unable to
// know if we encrypt a very small amount of data. However, if we encrypt
// a larger amount of data, the single difference becomes apparent:
WriteLn('-- Only the padding scheme differs --');
crypt.PaddingScheme := 0;
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
crypt.PaddingScheme := 3;
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
// Now examine the outputs:
// F6A201F8E0B6595FA20E4A212A2AD9A5046DAF29E8B35AD15CEE56A1A69F2A3A7B347A7C15E26E7A6760533C7A8E0D44
// F6A201F8E0B6595FA20E4A212A2AD9A5046DAF29E8B35AD15CEE56A1A69F2A3A292CA61D03A85E1AC39B50D4DA71691E
// We can see the output matches except for the last block, which is affected by the padding scheme.
// If we are able to easily use ECB mode w/ the other system
// we are trying to match, then eliminate the IV from the picture.
// If the encryption matches in ECB mode, but not in CBC mode,
// then we know all correct except for the IV.
// For example, you can see how the IV changes everything with CBC mode,
// but it's not used in ECB mode:
crypt.PaddingScheme := 0;
crypt.CipherMode := 'cbc';
WriteLn('-- Only the IV differs, CBC mode produces different output. --');
crypt.SetEncodedIV(ivHex1,'hex');
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
crypt.SetEncodedIV(ivHex2,'hex');
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
crypt.CipherMode := 'ecb';
WriteLn('-- Only the IV differs, ECB does not use the IV. The outputs are the same. --');
crypt.SetEncodedIV(ivHex1,'hex');
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
crypt.SetEncodedIV(ivHex2,'hex');
WriteLn(crypt.EncryptStringENC('HelloHelloHelloHelloHelloHelloHello'));
// If we can eliminate the padding scheme and IV from the degrees of freedom,
// then the only remaining likely differences are (1) the secret key,
// and (2) the input data itself.
// The secret key is composed of binary bytes of exactly KeyLength bits.
// For 256-bit AES encrytion, the key length is 256, and therefore the
// secret key is exactly 32 bytes. (32 * 8 bits/byte = 256 bits)
// If the secret key is derived from an arbitrary password string, then one must
// exactly duplicate the derivation scheme (such as PBKDF2, for example)
// The input bytes to the derivation scheme must also match. For example,
// is it the utf-8 byte representation of the password string that is used
// as the starting point for the derivation, or perhaps utf-16, or ANSI (1 byte per char)?
// Likewise, if the data being encrypted is a string, what byte representation of
// the string is being encrypted? If the bytes presented to the encryptor are different,
// then the output is different.
crypt.Free;
end;
// ---------------------------------------------------------------------------
begin
try
RunDemo;
except
on E: Exception do
WriteLn('Unhandled exception: ', E.ClassName, ': ', E.Message);
end;
WriteLn;
{$IFDEF MSWINDOWS}
WriteLn('Press Enter to exit...');
ReadLn;
{$ENDIF}
end.