Node.js

Get ZIP Directory Information as XML

See more Zip Examples

This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Node.js

NODEJS_PRELUDE

function chilkatExample() {

    var success = false;

    success = false;

    // Open an existing ZIP archive.
    var zip = new chilkat.Zip();

    success = zip.OpenZip("example.zip");
    if (success == false) {
        console.log(zip.LastErrorText);
        return;
    }

    // Get the ZIP directory information as XML.
    var xml = zip.GetDirectoryAsXML();

    console.log(xml);

    // Suppose the ZIP contains:

    // data/config/settings.json
    // docs/readme.txt
    // images/logo.png

    // The XML contains one element for each ZIP entry.
    // Example:
    // 
    // <?xml version="1.0" encoding="utf-8"?>
    // <zip_contents>
    //     <dir name="data">
    //         <dir name="config">
    //             <file>settings.json</file>
    //         </dir>
    //     </dir>
    //     <dir name="docs">
    //         <file>readme.txt</file>
    //     </dir>
    //     <dir name="images">
    //         <file>logo.png</file>
    //     </dir>
    // </zip_contents>

    zip.CloseZip();

    console.log("Done.");

}

chilkatExample();