Node.js

Get ZIP Directory Information as XML

See more Zip Examples

This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Node.js

NODEJS_PRELUDE

function chilkatExample() {

    var success = false;

    //  Open an existing ZIP archive.
    var zip = new chilkat.Zip();

    success = zip.OpenZip("example.zip");
    if (success == false) {
        console.log(zip.LastErrorText);
        return;
    }

    //  Get the ZIP directory information as XML.
    var xml = zip.GetDirectoryAsXML();

    console.log(xml);

    //  Suppose the ZIP contains:

    //  data/config/settings.json
    //  docs/readme.txt
    //  images/logo.png

    //  The XML contains one element for each ZIP entry.
    //  Example:
    //  
    //  <?xml version="1.0" encoding="utf-8"?>
    //  <zip_contents>
    //      <dir name="data">
    //          <dir name="config">
    //              <file>settings.json</file>
    //          </dir>
    //      </dir>
    //      <dir name="docs">
    //          <file>readme.txt</file>
    //      </dir>
    //      <dir name="images">
    //          <file>logo.png</file>
    //      </dir>
    //  </zip_contents>

    zip.CloseZip();

    console.log("Done.");

}

chilkatExample();