Node.js

Iterate over Direct Child Nodes by Index

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Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Node.js

NODEJS_PRELUDE

function chilkatExample() {

    var success = false;

    var xml = new chilkat.Xml();
    // child: Xml
    var child;

    // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
    success = xml.LoadXmlFile("get_child.xml");
    if (success !== true) {
        console.log(xml.LastErrorText);
        return;
    }

    // The NumChildren property contains the number of direct
    // child nodes.  Note: The child nodes under "xyz" are NOT
    // direct children of "root".  Therefore, the "root" node has
    // 7 direct children
    console.log("NumChildren = " + xml.NumChildren);

    // Iterate over the direct children by index. The first child
    // is at index 0.
    var i;
    for (i = 0; i <= xml.NumChildren - 1; i++) {
        //  access the tag and content directly by index:
        console.log(i + ": " + xml.GetChildTagByIndex(i) + " : " + xml.GetChildContentByIndex(i));

    }

    console.log("-----");

    // Do the same as the above loop, but get the child node
    // and access the Tag and Content properties:
    for (i = 0; i <= xml.NumChildren - 1; i++) {
        child = xml.GetChild(i);
        console.log(i + ": " + child.Tag + " : " + child.Content);

    }

    console.log("-----");

    // Do the same as the above loop, but instead of creating
    // a new object instance for each child, call GetChild2 to
    // update the object's reference instead.
    for (i = 0; i <= xml.NumChildren - 1; i++) {
        // Navigate to the Nth child.  
        success = xml.GetChild2(i);
        console.log(i + ": " + xml.Tag + " : " + xml.Content);
        // Navigate back up to the parent:
        success = xml.GetParent2();
    }

    console.log("-----");

    // Notice that the Content of the "xyz" node is empty.  This is correct.
    // The "xyz" node has no Content, but 2 direct children

}

chilkatExample();