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Lua

Iterate over Direct Children with a Specific Tag

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Demonstrates how to iterate over direct children having a specific tag.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat Lua Downloads

Lua
local chilkat = require("chilkat")

local xml = chilkat.Xml.new()
local child

-- The sample input XML is available at http://www.chilkatsoft.com/data/fruit.xml
local success = xml:load_xml_file("fruit.xml")
if not success then
    print(xml.last_error_text)
    return
end

--  Get the number of direct children having the tag "fruit";
local numWithTag = xml:num_children_having_tag("fruit")

if numWithTag > 0 then
    for i = 0, numWithTag - 1 do
        child = xml:get_nth_child_with_tag("fruit", i)
        print(i .. ": " .. child.tag .. " : " .. child.content)
    end

    print("-----")

    -- Do the same as the above loop, but instead of creating
    -- a new object instance for each child, call GetNthChildWithTag2 to
    -- update the object's reference instead.
    for i = 0, numWithTag - 1 do
        -- Navigate to the Nth child.
        success = xml:get_nth_child_with_tag2("fruit", i)
        print(i .. ": " .. xml.tag .. " : " .. xml.content)
        -- Navigate back up to the parent:
        success = xml:get_parent2()
    end

    print("-----")
end