Lua
Lua
Iterate over Direct Child Nodes by Index
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Demonstrates some ways to iterate over direct child nodes by index.The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:
<root>
<fruit color="red">apple</fruit>
<fruit color="green">pear</fruit>
<veg color="orange">carrot</veg>
<meat animal="cow">beef</meat>
<xyz>
<fruit color="blue">blueberry</fruit>
<veg color="green">broccoli</veg>
</xyz>
<fruit color="purple">grape</fruit>
<cheese color="yellow">cheddar</cheese>
</root>
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local chilkat = require("chilkat")
local xml = chilkat.Xml.new()
local child
-- The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
local success = xml:load_xml_file("get_child.xml")
if not success then
print(xml.last_error_text)
return
end
-- The NumChildren property contains the number of direct
-- child nodes. Note: The child nodes under "xyz" are NOT
-- direct children of "root". Therefore, the "root" node has
-- 7 direct children
print("NumChildren = " .. xml.num_children)
-- Iterate over the direct children by index. The first child
-- is at index 0.
for i = 0, xml.num_children - 1 do
-- access the tag and content directly by index:
print(i .. ": " .. xml:get_child_tag_by_index(i) .. " : " .. xml:get_child_content_by_index(i))
end
print("-----")
-- Do the same as the above loop, but get the child node
-- and access the Tag and Content properties:
for i = 0, xml.num_children - 1 do
child = xml:get_child(i)
print(i .. ": " .. child.tag .. " : " .. child.content)
end
print("-----")
-- Do the same as the above loop, but instead of creating
-- a new object instance for each child, call GetChild2 to
-- update the object's reference instead.
for i = 0, xml.num_children - 1 do
-- Navigate to the Nth child.
success = xml:get_child2(i)
print(i .. ": " .. xml.tag .. " : " .. xml.content)
-- Navigate back up to the parent:
success = xml:get_parent2()
end
print("-----")
-- Notice that the Content of the "xyz" node is empty. This is correct.
-- The "xyz" node has no Content, but 2 direct children.