Lua

Check if a MIME Part is Plain Text

Demonstrates the Chilkat Mime.IsPlainText method, which returns whether the Content-Type is exactly text/plain. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Inside a multipart/alternative, this is how you pick out the plain-text rendering — the fallback to show when HTML cannot be displayed, or the version to index for search. It is the specific counterpart to IsHtml.

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Lua

local chilkat = require("chilkat")

-- Demonstrates the Mime.IsPlainText method, which returns whether the Content-Type is text/plain.  It takes no arguments and applies to the current
-- part.  This example iterates the parts of a multipart message and reports which ones match.

local mime = chilkat.Mime.new()
local success = mime:load_mime_file("qa_data/multipart_message.eml")
if not success then
    print(mime.last_error_text)
    return
end

local n = mime.num_parts
local part = chilkat.Mime.new()
for i = 0, n - 1 do
    success = mime:part_at(i, part)
    if not success then
        print(mime.last_error_text)
        return
    end

    if part:is_plain_text() then
        print("Part " .. i .. " (" .. part.content_type .. ") is plain text.")
    end
end