Lua

HTTP multipart/form-data Upload

See more HTTP Examples

Demonstrates how to upload files to an HTTP server using a multipart/form-data POST. Lua

local chilkat = require("chilkat")

-- This example requires the Chilkat API to have been previously unlocked.
-- See Global Unlock Sample for sample code.

local http = chilkat.Http.new()

local req = chilkat.HttpRequest.new()
req.http_verb = "POST"
req.content_type = "multipart/form-data"
req.path = "rcvFormDataUpload.aspx"

-- Send an "Expect: 100-continue" header in the request.
-- This causes the HTTP server to end a 100-continue response
-- immediately after receiving the HTTP header.  The client
-- (Chilkat) will receive this intermediate response, and if
-- it's not an error response, it knows that the HTTP server will
-- accept the data that is forthcoming.
-- The alternative is to get an error response after trying to upload
-- the entire contents of the files.
req:add_header("Expect", "100-continue")

-- Call AddFileForUpload2 for each file to be uploaded in the HTTP multipart/form-data POST
-- To allow Chilkat to determine the content-type automatically based on file-extension,
-- call AddFileForUpload instead.

-- The 1st arg is the filename passed in the HTTP request.
-- The 2nd arg is the path in the local filesytem.
-- The file is not loaded into memory.  It is streamed directly from the file
-- when the HTTP POST is sent.
local success = req:add_file_for_upload2("starfish.jpg", "c:/qa_data/starfish.jpg", "image/jpg")
if not success then
    print(req.last_error_text)
    return
end

success = req:add_file_for_upload("something.pdf", "c:/qa_data/something.pdf")
if not success then
    print(req.last_error_text)
    return
end

-- Its also possible to add a file from a string:
success = req:add_string_for_upload("test.xml", "test.xml", "<abc>This is the test.xml content</abc>", "utf-8")
-- We'll assume success since no files are involved..

-- This sends the HTTP request (with 3 files being uploaded) to
-- http://www.mywebserver123abc.com/rcvFormDataUpload.aspx
local resp = chilkat.HttpResponse.new()
success = http:http_sreq("www.mywebserver123abc.com", 80, false, req, resp)
if not success then
    print(http.last_error_text)
    return
end

print("HTTP response status: " .. resp.status_code)
-- See the online reference documentation for
-- other information that can be obtained from the response object.

-- To send using SSL/TLS, do this instead.
-- This sends to https://www.mywebserver123abc.com/rcvFormDataUpload.aspx
success = http:http_sreq("www.mywebserver123abc.com", 443, true, req, resp)
if not success then
    print(http.last_error_text)
    return
end

print("HTTP response status: " .. resp.status_code)
-- See the online reference documentation for
-- other information that can be obtained from the response object.