Lianja

Get ZIP Directory Information as XML

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This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Lianja

llSuccess = .F.

llSuccess = .F.

// Open an existing ZIP archive.
loZip = createobject("CkZip")

llSuccess = loZip.OpenZip("example.zip")
if (llSuccess = .F.) then
    ? loZip.LastErrorText
    release loZip
    return
endif

// Get the ZIP directory information as XML.
lcXml = loZip.GetDirectoryAsXML()

? lcXml

// Suppose the ZIP contains:

// data/config/settings.json
// docs/readme.txt
// images/logo.png

// The XML contains one element for each ZIP entry.
// Example:
// 
// <?xml version="1.0" encoding="utf-8"?>
// <zip_contents>
//     <dir name="data">
//         <dir name="config">
//             <file>settings.json</file>
//         </dir>
//     </dir>
//     <dir name="docs">
//         <file>readme.txt</file>
//     </dir>
//     <dir name="images">
//         <file>logo.png</file>
//     </dir>
// </zip_contents>

loZip.CloseZip()

? "Done."


release loZip