Lianja Requires Chilkat v11.0.0+

Get ZIP Directory Information as XML

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This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Lianja

llSuccess = .F.

//  Open an existing ZIP archive.
loZip = createobject("CkZip")

llSuccess = loZip.OpenZip("example.zip")
if (llSuccess = .F.) then
    ? loZip.LastErrorText
    release loZip
    return
endif

//  Get the ZIP directory information as XML.
lcXml = loZip.GetDirectoryAsXML()

? lcXml

//  Suppose the ZIP contains:

//  data/config/settings.json
//  docs/readme.txt
//  images/logo.png

//  The XML contains one element for each ZIP entry.
//  Example:
//  
//  <?xml version="1.0" encoding="utf-8"?>
//  <zip_contents>
//      <dir name="data">
//          <dir name="config">
//              <file>settings.json</file>
//          </dir>
//      </dir>
//      <dir name="docs">
//          <file>readme.txt</file>
//      </dir>
//      <dir name="images">
//          <file>logo.png</file>
//      </dir>
//  </zip_contents>

loZip.CloseZip()

? "Done."


release loZip