(Lianja) Parse Multipart Binary Http Response

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf.

Note: This example requires Chilkat v11.0.0 or greater.

Chilkat Lianja Extension Download Chilkat Lianja Extension

llSuccess = .F.

// This example requires the Chilkat API to have been previously unlocked.
// See Global Unlock Sample for sample code.

loHttp = createobject("CkHttp")
loReq = createobject("CkHttpRequest")

// ...
// Insert code here to construct some kind of HTTP request.
// this example is to show how to parse a particular kind of response.
// ...
// ...

// Send the request (whatever it may be in your case) to get the HTTP response object.
loResp = createobject("CkHttpResponse")
llSuccess = loHttp.HttpSReq("www.somedomain.com",443,.T.,loReq,loResp)
if (llSuccess = .F.) then
    ? loHttp.LastErrorText
    release loHttp
    release loReq
    release loResp
    return
endif

// Get the response body (which is expected to be binary)
loRespBody = createobject("CkBinData")
loResp.GetBodyBd(loRespBody)

// For this example, the response body contains something like this:

// ------=_Part_21302_2029949381.1547401515443
// Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
// Content-Transfer-Encoding: 8bit
// Content-ID: <rootpart@ws.jboss.org>
// 
// <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
// ------=_Part_21302_2029949381.1547401515443
// Content-Type: application/octet-stream
// Content-Transfer-Encoding: binary
// Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
// 
// BINARY_CONTENT_HERE...
// 
// ------=_Part_21302_2029949381.1547401515443--
// 

// Load it into a Chilkat MIME object.
loMime = createobject("CkMime")
llSuccess = loMime.LoadMimeBd(loRespBody)
if (llSuccess = .F.) then
    ? loMime.LastErrorText
    release loHttp
    release loReq
    release loResp
    release loRespBody
    release loMime
    return
endif

lnNumParts = loMime.NumParts
if (lnNumParts < 2) then
    ? "Expected multipart MIME with at least 2 sub-parts."
    release loHttp
    release loReq
    release loResp
    release loRespBody
    release loMime
    return
endif

// Get the 1st sub-part, which is the XML.

loPart0 = createobject("CkMime")
loMime.PartAt(0,loPart0)

// Should be OK because we checked NumParts above..
lcXmlStr = loPart0.GetBodyDecoded()
? lcXmlStr
? "----"

// Save the 2nd part to a file.  (It is a .zip file in our test case..)

loPart1 = createobject("CkMime")
loMime.PartAt(1,loPart1)

llSuccess = loPart1.SaveBody("qa_output/attachedZip.zip")

// Alternatively, we could extract the binary data to a BinData and use elsewhere..
loZipData = createobject("CkBinData")
llSuccess = loPart1.GetBodyBd(loZipData)
llSuccess = loZipData.WriteFile("qa_output/attachedZip_again.zip")

? "OK."


release loHttp
release loReq
release loResp
release loRespBody
release loMime
release loPart0
release loPart1
release loZipData