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Check if a MIME Part is XML

Demonstrates the Chilkat Mime.IsXml method, which returns true only for text/xml or application/xml. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Identifying an XML part matters in machine-to-machine messaging — SOAP, EDI, structured data payloads — where you want to hand the body to an XML parser. Note it matches only the two canonical XML media types and not structured-suffix types like application/xhtml+xml, so check the exact type when those are relevant.

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llSuccess = .F.

//  Demonstrates the Mime.IsXml method, which returns whether the Content-Type is text/xml or application/xml.  It takes no arguments and applies to the current
//  part.  This example iterates the parts of a multipart message and reports which ones match.

loMime = createobject("CkMime")
llSuccess = loMime.LoadMimeFile("qa_data/multipart_message.eml")
if (llSuccess = .F.) then
    ? loMime.LastErrorText
    release loMime
    return
endif

n = loMime.NumParts
loPart = createobject("CkMime")

for i = 0 to n - 1
    llSuccess = loMime.PartAt(i,loPart)
    if (llSuccess = .F.) then
        ? loMime.LastErrorText
        release loMime
        release loPart
        return
    endif

    if (loPart.IsXml()) then
        ? "Part " + str(i) + " (" + loPart.ContentType + ") is XML."
    endif

next


release loMime
release loPart