Java

Iterate over Direct Child Nodes by Index

See more XML Examples

Demonstrates some ways to iterate over direct child nodes by index.

The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

Chilkat2 Java

import com.chilkatsoft.chilkat2.ChilkatException;
import com.chilkatsoft.chilkat2.Xml;

public class ChilkatExample {

    public static void main(String[] args) {
        Xml xml = new Xml();
        Xml child = null;

        // The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml
        try {
            xml.loadXmlFile("get_child.xml");
        } catch (ChilkatException e) {
            System.out.println(e.getLastErrorText());
            return;
        }

        // The NumChildren property contains the number of direct
        // child nodes.  Note: The child nodes under "xyz" are NOT
        // direct children of "root".  Therefore, the "root" node has
        // 7 direct children
        System.out.println("NumChildren = " + xml.getNumChildren());

        // Iterate over the direct children by index. The first child
        // is at index 0.
        for (int i = 0; i < xml.getNumChildren(); i++) {
            //  access the tag and content directly by index:
            System.out.println(i + ": " + xml.getChildTagByIndex(i) + " : " + xml.getChildContentByIndex(i));
        }

        System.out.println("-----");

        // Do the same as the above loop, but get the child node
        // and access the Tag and Content properties:
        for (int i = 0; i < xml.getNumChildren(); i++) {
            child = xml.getChild(i);
            System.out.println(i + ": " + child.getTag() + " : " + child.getContent());
            child.close();
        }

        System.out.println("-----");

        // Do the same as the above loop, but instead of creating
        // a new object instance for each child, call GetChild2 to
        // update the object's reference instead.
        for (int i = 0; i < xml.getNumChildren(); i++) {
            // Navigate to the Nth child.
            xml.getChild2(i);
            System.out.println(i + ": " + xml.getTag() + " : " + xml.getContent());
            // Navigate back up to the parent:
            xml.getParent2();
        }

        System.out.println("-----");

        // Notice that the Content of the "xyz" node is empty.  This is correct.
        // The "xyz" node has no Content, but 2 direct children.
    }
}