Java Requires Chilkat v11.0.0+

Parse Multipart Binary Http Response

See more HTTP Examples

This example demonstrates how to parse an HTTP response that is multipart and contains a binary file, such as a .zip or .pdf. Chilkat2 Java

import com.chilkatsoft.chilkat2.BinData;
import com.chilkatsoft.chilkat2.ChilkatException;
import com.chilkatsoft.chilkat2.Http;
import com.chilkatsoft.chilkat2.HttpRequest;
import com.chilkatsoft.chilkat2.HttpResponse;
import com.chilkatsoft.chilkat2.Mime;

public class ChilkatExample {

    public static void main(String[] args) {
        // This example requires the Chilkat API to have been previously unlocked.
        // See Global Unlock Sample for sample code.

        Http http = new Http();
        HttpRequest req = new HttpRequest();

        // ...
        // Insert code here to construct some kind of HTTP request.
        // this example is to show how to parse a particular kind of response.
        // ...
        // ...

        // Send the request (whatever it may be in your case) to get the HTTP response object.
        HttpResponse resp = new HttpResponse();
        try {
            http.httpSReq("www.somedomain.com", 443, true, req, resp);
        } catch (ChilkatException e) {
            System.out.println(e.getLastErrorText());
            return;
        }

        // Get the response body (which is expected to be binary)
        BinData respBody = new BinData();
        resp.getBodyBd(respBody);

        // For this example, the response body contains something like this:

        // ------=_Part_21302_2029949381.1547401515443
        // Content-Type: application/xop+xml; charset=UTF-8; type="text/xml"
        // Content-Transfer-Encoding: 8bit
        // Content-ID: <rootpart@ws.jboss.org>
        //
        // <env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'><env:Header></env:Header><env:Body>...</env:Body></env:Envelope>
        // ------=_Part_21302_2029949381.1547401515443
        // Content-Type: application/octet-stream
        // Content-Transfer-Encoding: binary
        // Content-Id: <fileArchivio-7d302908-4d64-43d3-bf4e-79ce806d43b3@ws.jboss.org>
        //
        // BINARY_CONTENT_HERE...
        //
        // ------=_Part_21302_2029949381.1547401515443--
        //

        // Load it into a Chilkat MIME object.
        Mime mime = new Mime();
        try {
            mime.loadMimeBd(respBody);
        } catch (ChilkatException e) {
            System.out.println(e.getLastErrorText());
            return;
        }

        int numParts = mime.getNumParts();
        if (numParts < 2) {
            System.out.println("Expected multipart MIME with at least 2 sub-parts.");
            return;
        }

        // Get the 1st sub-part, which is the XML.

        Mime part0 = new Mime();
        mime.partAt(0, part0);

        // Should be OK because we checked NumParts above..
        String xmlStr = part0.getBodyDecoded();
        System.out.println(xmlStr);
        System.out.println("----");

        // Save the 2nd part to a file.  (It is a .zip file in our test case..)

        Mime part1 = new Mime();
        mime.partAt(1, part1);

        part1.saveBody("qa_output/attachedZip.zip");

        // Alternatively, we could extract the binary data to a BinData and use elsewhere..
        BinData zipData = new BinData();
        part1.getBodyBd(zipData);
        zipData.writeFile("qa_output/attachedZip_again.zip");

        System.out.println("OK.");
    }
}