(Go) Traverse Direct Children via FirstChild / NextSibling, or LastChild / PreviousSibling

Demonstrates some ways to iterate over direct child nodes using the FirstChild / NextSibling and LastChild / PreviousSibling methods.

The input XML, available at http://www.chilkatsoft.com/data/fruit.xml, is this:

<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>

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    xml := chilkat.NewXml()
    // child is a Xml
    // nextSibling is a Xml
    // prevSibling is a Xml

    success := xml.LoadXmlFile("qa_data/xml/fruit.xml")
    if success != true {
        fmt.Println(xml.LastErrorText())
        xml.DisposeXml()
        return
    }

    // Iterate over the direct children by using FirstChild / NextSibling
    child := xml.FirstChild()
    bContinue := xml.LastMethodSuccess()
    for (bContinue == true) {
        fmt.Println(child.Tag(), " : ", child.Content())
        nextSibling := child.NextSibling()
        bContinue = child.LastMethodSuccess()
        child.DisposeXml()
        child = nextSibling
    }

    fmt.Println("-----")

    // Do the same, but with FirstChild2 / NextSibling2 to avoid
    // creating so many XML object instances:
    success = xml.FirstChild2()
    for success == true {
        fmt.Println(xml.Tag(), " : ", xml.Content())
        success = xml.NextSibling2()
    }

    // Revert back up to the parent:
    success = xml.GetParent2()

    fmt.Println("-----")

    // Iterate in reverse order using LastChild / PreviousSibling
    child = xml.LastChild()
    bContinue = xml.LastMethodSuccess()
    for (bContinue == true) {
        fmt.Println(child.Tag(), " : ", child.Content())
        prevSibling := child.PreviousSibling()
        bContinue = child.LastMethodSuccess()
        child.DisposeXml()
        child = prevSibling
    }

    fmt.Println("-----")

    // Do the same, but with LastChild2 / PreviousSibling2 to avoid
    // creating so many XML object instances:
    success = xml.LastChild2()
    for success == true {
        fmt.Println(xml.Tag(), " : ", xml.Content())
        success = xml.PreviousSibling2()
    }

    // Revert back up to the parent:
    success = xml.GetParent2()

    xml.DisposeXml()