Go

HTTP POST (Duplicate Simple HTML Form POST)

Demonstrates how to duplicate a simple HTML form POST. Go

    success := false

    // This example requires the Chilkat API to have been previously unlocked.
    // See Global Unlock Sample for sample code.

    req := chilkat.NewHttpRequest()
    http := chilkat.NewHttp()

    // This example simulates this FORM:
    // <form action="echoPost.asp" method="post">
    // First name: <input type="text" name="firstName"><br />
    // Last name: <input type="text" name="lastName"><br />
    // <input type="submit" value="Submit">
    // </form>
    // The online FORM is found at this URL:
    // https://www.chilkatsoft.com/simpleForm.html

    // Build an HTTP POST Request:
    req.SetHttpVerb("POST")

    // The FORM target is http://www.chilkatsoft.com/processPost.asp
    // An easy way of filling out most of the HTTP request object
    // is to call SetFromUrl:
    req.SetFromUrl("https://www.chilkatsoft.com/echoPost.asp")

    // Send form params using application/x-www-form-urlencoded
    req.SetContentType("application/x-www-form-urlencoded")

    // The only remaining task is to add the params to the 
    // HTTP request object:
    req.AddParam("firstName","Matt")
    req.AddParam("lastName","Jones")

    // Send the HTTP POST and get the response.
    // The POST is being sent to chilkatsoft.com, on port 443 (using TLS)
    domain := "chilkatsoft.com"
    port := 443
    tls := true

    // The HTTP POST is sent here:
    resp := chilkat.NewHttpResponse()
    success = http.HttpSReq(domain,port,tls,req,resp)
    if success == false {
        fmt.Println(http.LastErrorText())
        req.DisposeHttpRequest()
        http.DisposeHttp()
        resp.DisposeHttpResponse()
        return
    }

    // Display the HTML source of the page returned.
    fmt.Println(resp.BodyStr())

    req.DisposeHttpRequest()
    http.DisposeHttp()
    resp.DisposeHttpResponse()