Visual FoxPro

Continue SSH Tunnel Keyboard-Interactive Authentication

Demonstrates the Chilkat SshTunnel.ContinueKeyboardAuth method, which submits a response to a keyboard-interactive prompt. The only argument is the response text; for a request with multiple prompts, an XML response is supplied instead. It returns XML indicating the next prompt or the final result.

Background: This is the second half of the exchange started by StartKeyboardAuth. A server may issue several rounds of prompts, so a robust client loops: submit answers, read the returned XML, and continue until it sees success or failure. On success, BeginAccepting still must be called before the tunnel forwards traffic.

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LOCAL lnSuccess
LOCAL loTunnel
LOCAL lnSshPort
LOCAL lcInfoRequestXml
LOCAL lcPassword
LOCAL lcResult
LOCAL lnWaitForThreadExit

lnSuccess = 0

*  Demonstrates the SshTunnel.ContinueKeyboardAuth method, which submits a response to a
*  keyboard-interactive prompt.  The only argument is the response.  For multiple prompts, an XML
*  response is supplied instead.

loTunnel = CreateObject('Chilkat.SshTunnel')

*  The tunnel forwards accepted local connections to this destination through the SSH server.
loTunnel.DestHostname = "db.internal.example.com"
loTunnel.DestPort = 5432

*  Connect to the SSH server.  This performs the TCP/proxy connection and SSH handshake, but
*  does not authenticate yet.
lnSshPort = 22
lnSuccess = loTunnel.Connect("ssh.example.com",lnSshPort)
IF (lnSuccess = 0) THEN
    ? loTunnel.LastErrorText
    RELEASE loTunnel
    CANCEL
ENDIF

*  Begin keyboard-interactive authentication to receive the server's prompt(s).
lcInfoRequestXml = loTunnel.StartKeyboardAuth("mySshLogin")
IF (loTunnel.LastMethodSuccess = 0) THEN
    ? loTunnel.LastErrorText
    RELEASE loTunnel
    CANCEL
ENDIF

*  Normally you would not hard-code the password in source.  You should instead obtain it
*  from an interactive prompt, environment variable, or a secrets vault.
lcPassword = "mySshPassword"

*  Submit the response (typically the password).  The returned XML indicates the next prompt or
*  the final result.
lcResult = loTunnel.ContinueKeyboardAuth(lcPassword)
IF (loTunnel.LastMethodSuccess = 0) THEN
    ? loTunnel.LastErrorText
    RELEASE loTunnel
    CANCEL
ENDIF

? lcResult

lnWaitForThreadExit = 1
lnSuccess = loTunnel.CloseTunnel(lnWaitForThreadExit)
IF (lnSuccess = 0) THEN
    ? loTunnel.LastErrorText
    RELEASE loTunnel
    CANCEL
ENDIF

RELEASE loTunnel