Visual FoxPro
Visual FoxPro
Open a direct-tcpip Channel (SSH Port Forwarding)
See more SSH Examples
Demonstrates the Chilkat Ssh.OpenDirectTcpIpChannel method, which opens a direct-tcpip channel through the SSH server to a target host and port. The first argument is the target hostname and the second is the target port. It returns the channel number, or -1 on failure.
Background: This is SSH local port forwarding at the API level: the channel carries ordinary TCP traffic to a service that may be reachable only from the SSH server's network — a database, an internal web app, a message broker. The key detail is that the server resolves the target name, not your machine, so it must resolve and be reachable there. Supplying a numeric IPv4 address avoids remote DNS resolution entirely.
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LOCAL lnSuccess
LOCAL loSsh
LOCAL lnSshPort
LOCAL lcPassword
LOCAL lcTargetHostname
LOCAL lnTargetPort
LOCAL lnChannelNum
lnSuccess = 0
* Demonstrates the Ssh.OpenDirectTcpIpChannel method, which opens a direct-tcpip channel
* through the SSH server to a target host and port. The 1st argument is the target hostname
* and the 2nd is the target port. It returns the channel number, or -1 on failure.
loSsh = CreateObject('Chilkat.Ssh')
lnSshPort = 22
lnSuccess = loSsh.Connect("ssh.example.com",lnSshPort)
IF (lnSuccess = 0) THEN
? loSsh.LastErrorText
RELEASE loSsh
CANCEL
ENDIF
* Normally you would not hard-code the password in source. You should instead obtain it
* from an interactive prompt, environment variable, or a secrets vault.
lcPassword = "mySshPassword"
lnSuccess = loSsh.AuthenticatePw("mySshLogin",lcPassword)
IF (lnSuccess = 0) THEN
? loSsh.LastErrorText
RELEASE loSsh
CANCEL
ENDIF
* The target name is resolved by the SSH server, not by this computer, so it must be
* reachable from the server's network.
lcTargetHostname = "db.internal.example.com"
lnTargetPort = 5432
lnChannelNum = loSsh.OpenDirectTcpIpChannel(lcTargetHostname,lnTargetPort)
IF (lnChannelNum < 0) THEN
? loSsh.LastErrorText
RELEASE loSsh
CANCEL
ENDIF
? "Opened direct-tcpip channel: " + STR(lnChannelNum)
* The channel now carries ordinary TCP data to the target, tunneled over SSH.
loSsh.Disconnect()
RELEASE loSsh