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| (Excel) GetChild* methodsDemonstrates several of the GetChild* methods. The input XML, available at http://www.chilkatsoft.com/data/get_child.xml, is this: 
<root>
    <fruit color="red">apple</fruit>
    <fruit color="green">pear</fruit>
    <veg color="orange">carrot</veg>
    <meat animal="cow">beef</meat>
    <xyz>
        <fruit color="blue">blueberry</fruit>
        <veg color="green">broccoli</veg>
    </xyz>
    <fruit color="purple">grape</fruit>
    <cheese color="yellow">cheddar</cheese>
</root>
The output XML is this: <abc b="pear" c="orange" a="130">Test</abc> 
 Dim xml As Chilkat.Xml Set xml = Chilkat.NewXml ' The sample input XML is available at http://www.chilkatsoft.com/data/get_child.xml success = xml.LoadXmlFile("get_child.xml") If (success <> True) Then Debug.Print xml.LastErrorText Exit Sub End If ' The NumChildren property contains the number of direct ' child nodes. Note: The child nodes under "xyz" are NOT ' direct children of "root". Therefore, the "root" node has ' 7 direct children Debug.Print "NumChildren = "; xml.NumChildren ' Iterate over the direct children by index. The first child ' is at index 0. For i = 0 To xml.NumChildren - 1 ' access the tag and content directly by index: Debug.Print i; ": "; xml.GetChildTagByIndex(i); " : "; xml.GetChildContentByIndex(i) Next Debug.Print "-----" ' Do the same as the above loop, but get the child node ' and access the Tag and Content properties: For i = 0 To xml.NumChildren - 1 Set child = xml.GetChild(i) Debug.Print i; ": "; child.Tag; " : "; child.Content Next Debug.Print "-----" ' Do the same as the above loop, but instead of creating ' a new object instance for each child, call GetChild2 to ' update the object's reference instead. For i = 0 To xml.NumChildren - 1 ' Navigate to the Nth child. success = xml.GetChild2(i) Debug.Print i; ": "; xml.Tag; " : "; xml.Content ' Navigate back up to the parent: success = xml.GetParent2() Next Debug.Print "-----" ' Examine the result: Debug.Print xml.GetXml() | ||||
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