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(Excel) Parsing XML Children Having Identical Tags

Demonstrates how to deal with XML where child elements may have identical tags.

Download Excel Class Modules

Chilkat Excel Class Modules

'  This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

'  <?xml version="1.0" encoding="UTF-8" ?>
'  <someEntries>
'      <entry>
'          <id>123</id>
'          <updated>2017-07-19T05:19:57.761Z</updated>
'          <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
'          <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
'          <title>George Costanza</title>
'           <gd:name>
'              <gd:fullName>George Costanza</gd:fullName>
'              <gd:givenName>George</gd:givenName>
'              <gd:familyName>Costanza</gd:familyName>
'          </gd:name>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
'          <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
'          <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
'      </entry>
'  </someEntries>
' 

Dim xml As Chilkat.Xml
Set xml = Chilkat.NewXml


success = xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml")


numPhoneNumbers = xml.NumChildrenHavingTag("entry|*:phoneNumber")

i = 0
Do While i < numPhoneNumbers

    Set xPhoneNumber = xml.GetNthChildWithTag("entry|*:phoneNumber",i)
    Debug.Print xPhoneNumber.Content

    i = i + 1
Loop
Debug.Print "----"


numGroupMemberships = xml.NumChildrenHavingTag("entry|*:groupMembershipInfo")
i = 0
Do While i < numGroupMemberships

    Set xMembership = xml.GetNthChildWithTag("entry|*:groupMembershipInfo",i)
    Debug.Print xMembership.GetAttrValue("href")

    i = i + 1
Loop

 

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