(Excel) Parse the XML of an Excel (XLS) Spreadsheet

Demonstrate how to access various items from the XML of an XLS (Excel) Spreadsheet. Our sample data is shown below, and can be downloaded from http://www.chilkatsoft.com/data/ndc_nhric_labeler_codes_04_29_2015.xls

<?xml version="1.0" version="1.0" encoding="utf-8" ?>
<mso-application progid="Excel.Sheet"?>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:x="urn:schemas-microsoft-com:office:excel" xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet" xmlns:html="http://www.w3.org/TR/REC-html40">
    <DocumentProperties xmlns="urn:schemas-microsoft-com:office:office">
        <Version>14.00</Version>
    </DocumentProperties>
    <OfficeDocumentSettings xmlns="urn:schemas-microsoft-com:office:office">
        <AllowPNG />
    </OfficeDocumentSettings>
    <ExcelWorkbook xmlns="urn:schemas-microsoft-com:office:excel">
        <WindowHeight>7800</WindowHeight>
        <WindowWidth>12000</WindowWidth>
        <WindowTopX>105</WindowTopX>
        <WindowTopY>105</WindowTopY>
        <ProtectStructure>False</ProtectStructure>
        <ProtectWindows>False</ProtectWindows>
    </ExcelWorkbook>
    <Styles>
        <Style ss:ID="Default" ss:Name="Normal">
            <Alignment ss:Vertical="Top" />
            <Borders />
            <Font ss:FontName="Arial" />
            <Interior />
            <NumberFormat />
            <Protection />
        </Style>
        <Style ss:ID="s63">
            <Alignment ss:Vertical="Bottom" ss:WrapText="1" />
            <Font ss:FontName="Arial" x:Family="Swiss" ss:Bold="1" />
            <Interior ss:Color="#C0C0C0" ss:Pattern="Solid" />
        </Style>
        <Style ss:ID="s64">
            <NumberFormat ss:Format="@" />
        </Style>
    </Styles>
    <Worksheet ss:Name="NDCLabelerCode">
        <Table ss:ExpandedColumnCount="2" ss:ExpandedRowCount="8186" x:FullColumns="1" x:FullRows="1">
            <Column ss:Index="2" ss:Width="580.5" />
            <Row ss:AutoFitHeight="0" ss:Height="38.25">
                <Cell ss:StyleID="s63">
                    <Data ss:Type="String">NDC Labeler Code</Data>
                </Cell>
                <Cell ss:StyleID="s63">
                    <Data ss:Type="String">Firm Name</Data>
                </Cell>
            </Row>
            <Row>
                <Cell ss:StyleID="s64">
                    <Data ss:Type="String">0002</Data>
                </Cell>
                <Cell ss:StyleID="s64">
                    <Data ss:Type="String">Eli Lilly and Company</Data>
                </Cell>
            </Row>
...

Download Excel Class Modules Chilkat Excel Class Modules

Dim xlsDoc As Chilkat.Xml
Set xlsDoc = Chilkat.NewXml


success = xlsDoc.LoadXmlFile("myFiles/ndc_nhric_labeler_codes_04_29_2015.xls")
If (success <> True) Then
    Debug.Print xlsDoc.LastErrorText
    Exit Sub
End If

' This example will access the following pieces of data:
' NDC Labeler Code, Firm Name, 0002, Eli Lilly and Company, ...

' First navigate to the Worksheet named "NDCLabelerCode"

Set xWorksheet = xlsDoc.GetChildWithAttr("Worksheet","ss:Name","NDCLabelerCode")

' Next, get the Table node:

Set x = xWorksheet.GetChildWithTag("Table")

' How many immediate child nodes?

numChildren = x.NumChildren

' Loop over each Row and access the cell contents.

For i = 0 To (numChildren - 1)

    ' Navigate without creating new XML objects
    success = x.GetChild2(i)

    If (x.TagEquals("Row")) Then


        data0 = x.ChilkatPath("Cell[0]|Data|*")
        Debug.Print data0


        data1 = x.ChilkatPath("Cell[1]|Data|*")
        Debug.Print data1
    End If

    ' Navigate back up.
    success = x.GetParent2()
Next