DataFlex

Get ZIP Directory Information as XML

See more Zip Examples

This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

DataFlex

Use ChilkatAx-win32.pkg

Procedure Test
    Boolean iSuccess
    Handle hoZip
    String sXml
    String sTemp1

    Move False To iSuccess

    Move False To iSuccess

    // Open an existing ZIP archive.
    Get Create (RefClass(cComChilkatZip)) To hoZip
    If (Not(IsComObjectCreated(hoZip))) Begin
        Send CreateComObject of hoZip
    End

    Get ComOpenZip Of hoZip "example.zip" To iSuccess
    If (iSuccess = False) Begin
        Get ComLastErrorText Of hoZip To sTemp1
        Showln sTemp1
        Procedure_Return
    End

    // Get the ZIP directory information as XML.
    Get ComGetDirectoryAsXML Of hoZip To sXml

    Showln sXml

    // Suppose the ZIP contains:

    // data/config/settings.json
    // docs/readme.txt
    // images/logo.png

    // The XML contains one element for each ZIP entry.
    // Example:
    // 
    // <?xml version="1.0" encoding="utf-8"?>
    // <zip_contents>
    //     <dir name="data">
    //         <dir name="config">
    //             <file>settings.json</file>
    //         </dir>
    //     </dir>
    //     <dir name="docs">
    //         <file>readme.txt</file>
    //     </dir>
    //     <dir name="images">
    //         <file>logo.png</file>
    //     </dir>
    // </zip_contents>

    Send ComCloseZip To hoZip

    Showln "Done."


End_Procedure