C++

Check if a MIME Part is Plain Text

Demonstrates the Chilkat Mime.IsPlainText method, which returns whether the Content-Type is exactly text/plain. It takes no arguments and applies to the current part.

Note: The file path is relative to the application's current working directory. Absolute paths may also be used. Supply the path to your own file.

Background: Inside a multipart/alternative, this is how you pick out the plain-text rendering — the fallback to show when HTML cannot be displayed, or the version to index for search. It is the specific counterpart to IsHtml.

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C++

#include <CkMime.h>

void ChilkatSample(void)
    {
    bool success = false;

    //  Demonstrates the Mime.IsPlainText method, which returns whether the Content-Type is text/plain.  It takes no arguments and applies to the current
    //  part.  This example iterates the parts of a multipart message and reports which ones match.

    CkMime mime;
    success = mime.LoadMimeFile("qa_data/multipart_message.eml");
    if (success == false) {
        std::cout << mime.lastErrorText() << "\r\n";
        return;
    }

    int n = mime.get_NumParts();
    CkMime part;
    int i;
    for (i = 0; i <= n - 1; i++) {
        success = mime.PartAt(i,part);
        if (success == false) {
            std::cout << mime.lastErrorText() << "\r\n";
            return;
        }

        if (part.IsPlainText()) {
            std::cout << "Part " << i << " (" << part.contentType() << ") is plain text." << "\r\n";
        }

    }
    }