(Chilkat2-Python) Get ZIP Directory Information as XML

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This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Note: This example requires Chilkat v11.0.0 or greater.

Chilkat2 Python Downloads install with pip pip3 install chilkat2 or download... Python Module for Windows, Linux, Alpine Linux, MacOS

import sys
import chilkat2

success = False

success = False

# Open an existing ZIP archive.
zip = chilkat2.Zip()

success = zip.OpenZip("example.zip")
if (success == False):
    print(zip.LastErrorText)
    sys.exit()

# Get the ZIP directory information as XML.
xml = zip.GetDirectoryAsXML()

print(xml)

# Suppose the ZIP contains:

# data/config/settings.json
# docs/readme.txt
# images/logo.png

# The XML contains one element for each ZIP entry.
# Example:
# 
# <?xml version="1.0" encoding="utf-8"?>
# <zip_contents>
#     <dir name="data">
#         <dir name="config">
#             <file>settings.json</file>
#         </dir>
#     </dir>
#     <dir name="docs">
#         <file>readme.txt</file>
#     </dir>
#     <dir name="images">
#         <file>logo.png</file>
#     </dir>
# </zip_contents>

zip.CloseZip()

print("Done.")