Chilkat2-Python

Continue SSH Tunnel Keyboard-Interactive Authentication

Demonstrates the Chilkat SshTunnel.ContinueKeyboardAuth method, which submits a response to a keyboard-interactive prompt. The only argument is the response text; for a request with multiple prompts, an XML response is supplied instead. It returns XML indicating the next prompt or the final result.

Background: This is the second half of the exchange started by StartKeyboardAuth. A server may issue several rounds of prompts, so a robust client loops: submit answers, read the returned XML, and continue until it sees success or failure. On success, BeginAccepting still must be called before the tunnel forwards traffic.

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import sys
import chilkat2

success = False

# Demonstrates the SshTunnel.ContinueKeyboardAuth method, which submits a response to a
# keyboard-interactive prompt.  The only argument is the response.  For multiple prompts, an XML
# response is supplied instead.

tunnel = chilkat2.SshTunnel()

# The tunnel forwards accepted local connections to this destination through the SSH server.
tunnel.DestHostname = "db.internal.example.com"
tunnel.DestPort = 5432

# Connect to the SSH server.  This performs the TCP/proxy connection and SSH handshake, but
# does not authenticate yet.
sshPort = 22
success = tunnel.Connect("ssh.example.com",sshPort)
if (success == False):
    print(tunnel.LastErrorText)
    sys.exit()

# Begin keyboard-interactive authentication to receive the server's prompt(s).
infoRequestXml = tunnel.StartKeyboardAuth("mySshLogin")
if (tunnel.LastMethodSuccess == False):
    print(tunnel.LastErrorText)
    sys.exit()

# Normally you would not hard-code the password in source.  You should instead obtain it
# from an interactive prompt, environment variable, or a secrets vault.
password = "mySshPassword"

# Submit the response (typically the password).  The returned XML indicates the next prompt or
# the final result.
result = tunnel.ContinueKeyboardAuth(password)
if (tunnel.LastMethodSuccess == False):
    print(tunnel.LastErrorText)
    sys.exit()

print(result)

waitForThreadExit = True
success = tunnel.CloseTunnel(waitForThreadExit)
if (success == False):
    print(tunnel.LastErrorText)
    sys.exit()