B4X

Parsing XML Children Having Identical Tags

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Demonstrates how to deal with XML where child elements may have identical tags. B4X

Dim success As Boolean = False

'  This example will get the phoneNumber's and groupMembershihpInfo's from the following XML:

'  <?xml version="1.0" encoding="UTF-8" ?>
'  <someEntries>
'      <entry>
'          <id>123</id>
'          <updated>2017-07-19T05:19:57.761Z</updated>
'          <app:edited xmlns:app="http://www.w3.org/2007/app">2017-07-19T05:19:57.761Z</app:edited>
'          <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact"/>
'          <title>George Costanza</title>
'           <gd:name>
'              <gd:fullName>George Costanza</gd:fullName>
'              <gd:givenName>George</gd:givenName>
'              <gd:familyName>Costanza</gd:familyName>
'          </gd:name>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#home">(555) 123-4567</gd:phoneNumber>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#mobile">(555) 444-8877</gd:phoneNumber>
'          <gd:phoneNumber rel="http://schemas.google.com/g/2005#work">(555) 678-1111</gd:phoneNumber>
'          <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/123"/>
'          <gContact:groupMembershipInfo deleted="false" href="http://www.google.com/456"/>
'      </entry>
'  </someEntries>
'  

Dim xml As ChilkatXml
xml.Initialize

success = xml.LoadXmlFile("qa_data/xml/georgeCostanza.xml")

Dim numPhoneNumbers As Int = xml.NumChildrenHavingTag("entry|*:phoneNumber")
Dim i As Int = 0
Do While i < numPhoneNumbers
    Dim xPhoneNumber As ChilkatXml = xml.GetNthChildWithTag("entry|*:phoneNumber", i)
    Log(xPhoneNumber.Content)

    i = i + 1
Loop
Log("----")

Dim numGroupMemberships As Int = xml.NumChildrenHavingTag("entry|*:groupMembershipInfo")
i = 0
Do While i < numGroupMemberships
    Dim xMembership As ChilkatXml = xml.GetNthChildWithTag("entry|*:groupMembershipInfo", i)
    Log(xMembership.GetAttrValue("href"))

    i = i + 1
Loop