AutoIt Requires Chilkat v11.0.0+

Get ZIP Directory Information as XML

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This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

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Local $bSuccess = False

;  Open an existing ZIP archive.
$oZip = ObjCreate("Chilkat.Zip")

$bSuccess = $oZip.OpenZip("example.zip")
If ($bSuccess = False) Then
    ConsoleWrite($oZip.LastErrorText & @CRLF)
    Exit
EndIf

;  Get the ZIP directory information as XML.
Local $sXml = $oZip.GetDirectoryAsXML()

ConsoleWrite($sXml & @CRLF)

;  Suppose the ZIP contains:

;  data/config/settings.json
;  docs/readme.txt
;  images/logo.png

;  The XML contains one element for each ZIP entry.
;  Example:
;  
;  <?xml version="1.0" encoding="utf-8"?>
;  <zip_contents>
;      <dir name="data">
;          <dir name="config">
;              <file>settings.json</file>
;          </dir>
;      </dir>
;      <dir name="docs">
;          <file>readme.txt</file>
;      </dir>
;      <dir name="images">
;          <file>logo.png</file>
;      </dir>
;  </zip_contents>

$oZip.CloseZip 

ConsoleWrite("Done." & @CRLF)