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Create a Remote Directory on an SFTP Server

Demonstrates the Chilkat SFtp.CreateDir method, which creates a remote directory. The only argument is the directory path.

Background: The key caveat is that parent directories are not necessarily created automatically — creating a/b/c in one call may fail if a/b does not already exist. To build a deep path, create each level in turn (or check existence first with FileExists). Attempting to create a directory that already exists is generally an error, so guard against it when re-running a job.

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Local $bSuccess = False

;  Demonstrates the SFtp.CreateDir method, which creates a remote directory.  The only argument
;  is the directory path.

$oSftp = ObjCreate("Chilkat.SFtp")

;  Connect, authenticate, and initialize the SFTP subsystem.
Local $iPort = 22
$bSuccess = $oSftp.Connect("sftp.example.com",$iPort)
If ($bSuccess = False) Then
    ConsoleWrite($oSftp.LastErrorText & @CRLF)
    Exit
EndIf

;  Normally you would not hard-code the password in source.  You should instead obtain it
;  from an interactive prompt, environment variable, or a secrets vault.
Local $sPassword = "mySshPassword"

$bSuccess = $oSftp.AuthenticatePw("mySshLogin",$sPassword)
If ($bSuccess = False) Then
    ConsoleWrite($oSftp.LastErrorText & @CRLF)
    Exit
EndIf

$bSuccess = $oSftp.InitializeSftp()
If ($bSuccess = False) Then
    ConsoleWrite($oSftp.LastErrorText & @CRLF)
    Exit
EndIf

;  Create a remote directory.  Parent directories are not necessarily created automatically, so
;  create each level if you need a full path.
$bSuccess = $oSftp.CreateDir("subdir/newfolder")
If ($bSuccess = False) Then
    ConsoleWrite($oSftp.LastErrorText & @CRLF)
    Exit
EndIf

ConsoleWrite("Directory created." & @CRLF)

$oSftp.Disconnect