Classic ASP Requires Chilkat v11.0.0+

Get ZIP Directory Information as XML

See more Zip Examples

This example demonstrates how to use the GetDirectoryAsXML method to retrieve information about the contents of a ZIP archive as an XML document.

The returned XML describes the files currently contained in the ZIP object

Classic ASP

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<%
success = 0

'  Open an existing ZIP archive.
set zip = Server.CreateObject("Chilkat.Zip")

success = zip.OpenZip("example.zip")
If (success = 0) Then
    Response.Write "<pre>" & Server.HTMLEncode( zip.LastErrorText) & "</pre>"
    Response.End
End If

'  Get the ZIP directory information as XML.
xml = zip.GetDirectoryAsXML()

Response.Write "<pre>" & Server.HTMLEncode( xml) & "</pre>"

'  Suppose the ZIP contains:

'  data/config/settings.json
'  docs/readme.txt
'  images/logo.png

'  The XML contains one element for each ZIP entry.
'  Example:
'  
'  <?xml version="1.0" encoding="utf-8"?>
'  <zip_contents>
'      <dir name="data">
'          <dir name="config">
'              <file>settings.json</file>
'          </dir>
'      </dir>
'      <dir name="docs">
'          <file>readme.txt</file>
'      </dir>
'      <dir name="images">
'          <file>logo.png</file>
'      </dir>
'  </zip_contents>

zip.CloseZip 

Response.Write "<pre>" & Server.HTMLEncode( "Done.") & "</pre>"

%>
</body>
</html>